Suppose that for f, f,.. is a sequence defined as follows. fo = 5, f, = 16, fk = 7f -1- 10f-2 for every integer k 2 2 Prove that f. = 3. 2" + 2. 5" for each integer n 2 0. Proof by strong mathematical induction: Let the property P(n) be the equation f.= 3. 2" + 2 · 5". We will show that P(n) is true for every integer n 2 o. Show that P(0) and P(1) are true: Select P(0) from the choices below. O P(0) = 3- 20 + 2- 50 O f = 3- 20 + 2- 50 Ofo = 5 O P(0) = fo Select P(1) from the choices below. O P(1) = f Of = 16 O, = 3-2 +2-5 O P(1) = 3 - 21 + 2.51 P(0) and P(1) are true because 3· 20 + 2.50 = 5 and 3- 21 + 2.5 = 16. Show that for every integer k2 1, if P(i) is true for each integer i from 0 through k, then P(k + 1) is true: Let k be any integer with k 2 1, and suppose that for every integer i with o sisk, f,= This is the -Select-- We must show that f 1= Now, by definition of fo, f, f2., fk +1 = Apply the inductive hypothesis to f, and f , and complete the proof as a free response. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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**Proof by Strong Mathematical Induction**

Consider a sequence \( f_0, f_1, f_2, \ldots \) defined as follows:

- \( f_0 = 5 \), \( f_1 = 16 \)
- \( f_k = 7f_{k-1} - 10f_{k-2} \) for every integer \( k \geq 2 \)

We aim to prove that \( f_n = 3 \cdot 2^n + 2 \cdot 5^n \) for each integer \( n \geq 0 \).

**Base Cases: Show that \( P(0) \) and \( P(1) \) are true.**

Select \( P(0) \) from the choices below:

- \( P(0) = 3 \cdot 2^0 + 2 \cdot 5^0 \)
- \( f_0 = 3 \cdot 2^0 + 2 \cdot 5^0 \)
- \( f_0 = 5 \)
- \( P(0) = f_0 \)

Select \( P(1) \) from the choices below:

- \( P(1) = f_1 \)
- \( f_1 = 16 \)
- \( f_1 = 3 \cdot 2^1 + 2 \cdot 5^1 \)
- \( P(1) = 3 \cdot 2^1 + 2 \cdot 5^1 \)

\( P(0) \) and \( P(1) \) are true because \( 3 \cdot 2^0 + 2 \cdot 5^0 = 5 \) and \( 3 \cdot 2^1 + 2 \cdot 5^1 = 16 \).

**Inductive Step: Show that for every integer \( k \geq 1 \), if \( P(i) \) is true for each integer \( i \) from 0 through \( k \), then \( P(k + 1) \) is true.**

Let \( k \) be any integer with \( k \geq 1 \), and suppose that for every integer \( i \) with \( 0 \leq i \leq
Transcribed Image Text:**Proof by Strong Mathematical Induction** Consider a sequence \( f_0, f_1, f_2, \ldots \) defined as follows: - \( f_0 = 5 \), \( f_1 = 16 \) - \( f_k = 7f_{k-1} - 10f_{k-2} \) for every integer \( k \geq 2 \) We aim to prove that \( f_n = 3 \cdot 2^n + 2 \cdot 5^n \) for each integer \( n \geq 0 \). **Base Cases: Show that \( P(0) \) and \( P(1) \) are true.** Select \( P(0) \) from the choices below: - \( P(0) = 3 \cdot 2^0 + 2 \cdot 5^0 \) - \( f_0 = 3 \cdot 2^0 + 2 \cdot 5^0 \) - \( f_0 = 5 \) - \( P(0) = f_0 \) Select \( P(1) \) from the choices below: - \( P(1) = f_1 \) - \( f_1 = 16 \) - \( f_1 = 3 \cdot 2^1 + 2 \cdot 5^1 \) - \( P(1) = 3 \cdot 2^1 + 2 \cdot 5^1 \) \( P(0) \) and \( P(1) \) are true because \( 3 \cdot 2^0 + 2 \cdot 5^0 = 5 \) and \( 3 \cdot 2^1 + 2 \cdot 5^1 = 16 \). **Inductive Step: Show that for every integer \( k \geq 1 \), if \( P(i) \) is true for each integer \( i \) from 0 through \( k \), then \( P(k + 1) \) is true.** Let \( k \) be any integer with \( k \geq 1 \), and suppose that for every integer \( i \) with \( 0 \leq i \leq
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