Suppose that a random sample of 16 recently sold houses in a certain city has a mean sales price of $280,000, with a standard deviation of $11,000. Under the assumption that house prices are normally distributed, find a 90% confidence interval for the mean sales price of all houses in this city. Give the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to the nearest whole number. (If necessary, consult a list of formulas.) Lower limit: S Upper limit: $ X

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SLICE NAME Confidence Intervals and Hypothesis Testing TOPIC NAME Confidence interval for the population mean: Use of the t distribution
Suppose that a random sample of 16 recently sold houses in a certain
city has a mean sales price of $280,000, with a standard deviation of $11,000.
Under the assumption that house prices are normally distributed, find a
90% confidence interval for the mean sales price of all houses in this city.
Give the lower limit and upper limit of the 90% confidence interval.
Carry your intermediate computations to at least three decimal places.
Round your answers to the nearest whole number. (If necessary, consult
a list of formulas.)
Lower limit: S
Upper limit: $
X
?
B
H
1
F
Aa
Transcribed Image Text:Suppose that a random sample of 16 recently sold houses in a certain city has a mean sales price of $280,000, with a standard deviation of $11,000. Under the assumption that house prices are normally distributed, find a 90% confidence interval for the mean sales price of all houses in this city. Give the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to the nearest whole number. (If necessary, consult a list of formulas.) Lower limit: S Upper limit: $ X ? B H 1 F Aa
Expert Solution
Step 1

We have given that

Sample size (n) = 16
Sample mean (x̅) = 280000
Standard deviations (s) = 11000
Confidence level (c) = 90% = 0.90
Significance level (α) = 1- 0.90 = 0.10

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