Use the given confidence interval to find the margin of error and the sample proportion.se Home(0.756,0.780)gnments(Type an integer or a decimal.)E3Dlebookpter Contentsxtltimedia Libraryudy Planpols for Successccessible ResourcesSkills for SuccessHelp me solve thisView an exampleGet more help-Glear allCopyright 2021 Pearson Education Inc. All rights reserved. Terms of Use | Privacy PolicyType here to search20

Given: confidence interval ( 0.756 , 0.78 ) Need to find sample mean(x̄) and margin of error(ME) .

Answered: Use the given confidence interval to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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[DL] SPRING 2021: MATH 117 with Support [202130 CRNS 33063 and 33064] O UNIT 4: ASSIGNMENTS [UNIT 4] HW: C ... A fitness center is interested in finding a 90% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 219 members were looked at and their mean number of visits per week was 3.2 and the standard deviation was 1.6. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ?v distribution. b. With 90% confidence the population mean number of visits per week is between and visits. c. If many groups of 219 randomly selected members are studied, then a different confidence percent of these confidence interval would be produced from each group. About intervals will contain the true population mean number of visits per week and about percent will not contain the true population mean number of visits per week. Hint: Hints Video [+] MacBook
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q29E- Answer to part D was - (0.0801, 0.1699)
T17
Suppose that the lengths, in inches, of adult corn snakes are normally distributed with an unknown mean and standard deviation. A random sample of 38 snakes is taken and gives a sample mean of 53 inches and a sample standard deviation of 6 inches. Find a 95% confidence interval estimate for the population mean using the Student's t-distribution. Select the correct answer below: (51.36,54.64), with ME=(1.686)(638√) (51.03,54.97), with ME=(2.024)(638√) (51.00,55.00), with ME=(2.026)(637√) (51.03,54.97), with ME=(2.026)(638√) (51.34,54.66), with ME=(1.686)(637√) (51.34,54.66), with ME=(1.687)(637√)
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Use the given confidence interval to find (0.756,0.780) E3D (Type an integer integer or a decimal.)