11 pointUse the given degree of confidence and sample data toconstruct a confidence interval for the populationproportion p. Round your final answers to 3 decimalplaces. Of 150 adults selected randomly from onetown, 30 of them smoke. Construct a 99% confidenceinterval for the true percentage of all adults in thetown that smoke.You will need to calculate the margin of error, followedby the lower and upper end of the confidence interval.Margin of Error:choose your answer...Confidence Interval:choose your answer...< pchoose your answer...V

Answered: Image /qna-images/answer/17c9e5ab-9d1a-4052-bfaf-4898142566a5.jpg

Answered: Use the given degree of confidence and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Determine whether the statement below makes sense or does not make sense. Explain clearly. Based on our sample, the 95% confidence interval for the mean amount of television watched by adults in a nation is 2.9 to 4.3 hours per day. Therefore, there is 95% chance that the mean for all adults in the nation will fall somewhere in this range and a 5% chance that it will not. C Choose the correct answer below. O A. The statement makes sense. There is 5% probability that the confidence interval limits do not contain the true value of the sample mean, so the probability it does not contain the true value of the population mean is also 5%. O B. The statement does not make sense. The population mean is a fixed constant that either falls within the confidence interval or it does not. There is no probability associated with this. O C. The statement does not make sense. The probability the population mean is greater than the upper limit is 5% and the probability it is less than the lower limit is…
You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You decide on the 90% confidence level and a margin of error of 2%. A pilot survey reveals that 5 of the 44 sampled hold two or more jobs. (Use t Distribution Table & z Distribution Table.) How many in the workforce should be interviewed to meet your requirements? (Round z-score to 2 decimal places. Round up your answer to the next whole number.)
K A R Explain how finding a confidence interval for a population variance is different from finding a confidence interval for a population mean or proportion. Choose the correct answer below. OA. Unlike a confidence interval for a population variance, a confidence interval for a population mean or proportion does not have a margin or error. The left and right endpoints must be calculated separately. OB. Unlike a confidence interval for a population variance, a confidence interval for a population mean or proportion does not have a margin or error. The left and right endpoints must not be calculated separately OC. Unlike a confidence interval for a population mean or proportion, a confidence interval for a population variance does not have a margin or error. The left and right endpoints must not be calculated separately OD. Unlike a confidence interval for a population mean or proportion, a confidence interval for a population variance does not have a margin or error. The left and right…
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of $125.00. Assume the population standard deviation is $19.30 Construct a 90% confidence interval for the population mean. The 90% confidence interval is___________________________. (Round to two decimal places as needed.)
A new fertilizer was applied to the soil of 123 bean plants. 85% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to %
Question Emilio wants to estimate the percentage of people who have a financial adviser. He surveys 350 individuals and finds that 76 have a financial adviser. Identify the values needed to calculate a confidence interval at the 99% confidence level. Then find the confidence interval. Z0.10 Z0.05 Z0.025 Z0.01 Z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of common z-scores above. • Round the final answer to three decimal places. Provide your answer below: Next « Previous DII DD 80 F9 F10 F11 F12 F5 F7 F8 F3 F4
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I need p, q, & n Thankyou !
Virginia wants to estimate the percentage of students who live more than three miles from the school. She wants to create a 95% confidence interval which has a margin of error of at most 5%. How many students should be polled to create the confidence interval? z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of values above.
Janet wants to estimate the percentage of people who have been required to take a drug test for work. She surveys 250 individuals and finds that 175 have taken a drug test for work. Identify the values needed to calculate a confidence interval at the 98% confidence level. Then use Excel to find the confidence interval. Round the final answer to three decimal places. Provide your answer below:
Use the sample data and confidence level given below. A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=979 and x=530 who said "yes." Use a 95% confidence level. Find the best point estimate of the population proportion p, q, p, q, e, n
A poll of 2612 U.S. adults found that 15% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: _______% to ______% Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: ________% to ________% Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: ________% to ______% The more error we allow, the less precise our estimate. Therefore, as the confidence…

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