Suppose that a movie is being filmed in some city. An action shot requires an object to be thrown upward with an initial velocity of 96 feet per second off the top of a building, a height of 640 feet. The height h(t) in feet of the object after t seconds is given by the function h(t) = - 16r + 96t + 640. (a) Find the height of the object at t= 0 seconds, t= 3 seconds, t= 6 seconds, and t=9 seconds. (b) Explain why the height of the object increases and then decreases as time passes. (c) Factor the polynomial – 16 + 96t + 640.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Suppose that a movie is being filmed in some city. An action shot requires an object to be thrown upward with an initial velocity of 96 feet per second off the top of a
building, a height of 640 feet. The height h(t) in feet of the object after t seconds is given by the function h(t) = - 16t + 96t + 640.
(a) Find the height of the object at t = 0 seconds, t= 3 seconds, t= 6 seconds, and t= 9 seconds.
(b) Explain why the height of the object increases and then decreases as time passes.
(c) Factor the polynomial - 16t + 96t + 640.
(a) The height of the object at t=0 seconds is
ft.
Transcribed Image Text:Suppose that a movie is being filmed in some city. An action shot requires an object to be thrown upward with an initial velocity of 96 feet per second off the top of a building, a height of 640 feet. The height h(t) in feet of the object after t seconds is given by the function h(t) = - 16t + 96t + 640. (a) Find the height of the object at t = 0 seconds, t= 3 seconds, t= 6 seconds, and t= 9 seconds. (b) Explain why the height of the object increases and then decreases as time passes. (c) Factor the polynomial - 16t + 96t + 640. (a) The height of the object at t=0 seconds is ft.
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