The height (feet) of an object moving vertically is given by s = - 16t + 208t + 156, where t is i seconds. Find the object's velocity at t= 5, its maximum height and when it occurs, and its velocity when s=0.
The height (feet) of an object moving vertically is given by s = - 16t + 208t + 156, where t is i seconds. Find the object's velocity at t= 5, its maximum height and when it occurs, and its velocity when s=0.
Related questions
Question

Transcribed Image Text:The height (feet) of an object moving vertically is given by \( s = -16t^2 + 208t + 156 \), where \( t \) is in seconds. Find the object's velocity at \( t = 5 \), its maximum height and when it occurs, and its velocity when \( s = 0 \).
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
