Suppose students who enter kindergarten at Stanley Elementary School take a standardized vocabulary assessment. The scores on the vocabularyassessment produce a normal density curve as shown.5475From the graph shown, give the mean and median, and then use the 68-95-99.7% (empirical) rule to estimate the standard deviation of the vocabularyassessment.For a nonstandard normal density curve, about 68% of scores are within 1within 2196The median vocabulary assessment score ispoints.standard deviations of the mean, and 99.7% are within 3Because 99.7% of values are within 3points and the mean vocabulary assessment score is 75standard deviations of the mean* standard deviations between 96 points and 54 points.standard deviation of the mean, about 95% arestandard deviations of the mean.To estimate the standard deviation, take the difference between 96 points and 54 points and divide by 6The standard deviation for the nonstandard normal density curve shown ispoints.Ithere should be about

the empirical rule predicts that in normal distributions, 68% of observations fall within the first…

Answered: Suppose students who enter kindergarten…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A. Which one is greater the mean or the median? Which one is better measured of the center the median or the mean? Show work B. Find the mode C. Find the median D. Find the mean (even though we must round to the one decimal place to make computations easy round you’re mean to the nearest minute)
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.05 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). E Click the icon to view the data. In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Ha = 0 H,: Ha #0 O B. Ho: Ha #0 H1: Hd =0 O C. Ho: Ha #0 O D. Ho: Ha = 0 H1: Hd 0
Among freshmen at a certain university, scores on the Math SAT followed the normal curve, with an average of 550 and an SD of 100. The SAT score of a student whose score is at the 99th percentile is closest to what value? Group of answer choices 780 400 760 805
A company decides to investigate the amount of sick leave taken by its employees. A sample of seven employees yields the following numbers of days of sick leave taken in the past year. 1 1 3 0 0 63 Use this information to answer parts a through c. a. Find and interpret the range. The range is 6 days. Choose the correct interpretation of the range below. A. The largest difference between the mean and any other value is equal to the range. B. The number of days separating the fewest and most sick days taken is equal to the range. C. The range represents the average distance of an observation from the mean. D. The range gives the most useful value for measuring the spread of the data.
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Corporate Farms. The U.S. Census Bureau estimates the mean value of the land and buildings per corporate farm. Those estimates are published in the Census of Agriculture. Suppose that an estimate, x, is obtained and that the margin of error is $1000. Does this result imply that the true mean, μ, is within $1000 of the estimate? Explain your answer.
14. The range is defined as the: a. variability of the data with reference to extreme scores. b. the variability of the data with reference to the mean. c. variability of the data in terms of how many subjects achieved each value of the variable. d. SS/n
Please answer the questions in the photo. Thank You!
1:15 (a) Which variable is the explanatory variable? OA. One of the biggest factors in determining the value of a home is the square footage. The accompanying data represent the square footage and selling price (in thousands of dollars) for a random sample of homes for sale in a certain region. Complete parts (a) through (h) below. Click the icon to view the housing data. Square Footage Selling Price (b) Draw a scatter diagram of the data. Choose the correct scatter diagram below. Ay 4500- 000 1000 mylab.pearson.com/ + ® : 3 4500 Data Table Q Square Footage, x 2148 3231 1177 1988 3064 2735 4146 2215 2625 1629 1773 3887 Print ||| OB. r= 0.899 (Round to three decimal places as needed.) = AX 4500- 1000+++ 150 750 Q (c) Determine the linear correlation coefficient between square footage and asking price. Done Ay 750- Vo) 1 LTE2 150- O 1000 Selling Price ($000s), y D 371.1 382.2 197.6 339.9 614.9 364.7 632.7 377.7 427.5 285.9 268.9 701.4 4500 .... .... Q X D. Ay 750- 41% 150+ 1000 4500
Please refer to the picture attached.
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.5 degrees. Low Temperature (o F) 40 - 44 45 - 49 50 - 54 55 - 59 60 – 64 D Frequency 2 9. ... The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.) Which of the following best describes the relationship between the computed mean and the actual mean? O A. The computed mean is close to the actual mean because the difference between the means is more than 5% of the actual mean. B. The computed mean is not close to the actual mean because the difference between the means is less than 5% of the actual mean. C. The computed mean is not close to the actual mean because the difference between the means is more than 5% of the actual mean. D. The computed mean is close to the actual mean because the difference between the means is less than 5% of the actual mean.

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