Preliminary information:A random variable X is said to have a beta distribution if its PDF is given by:1fx (x) = b-aX~Beta(a. B.a, b)A random variable Y is said to have a standard beta distribution if its PDF is given by:The mode of Y is given by:α-1B-1² ( ² = 2 ) *¹ (ta) ³-¹r(x+B)(x-aΓ(α)Γ(β)fy(y) =r(a)r (B)Y~Beta(a, B)One may transform from X~Beta(a, ß, a, b) to Y~Beta(a, ß) by letting y = (x-a)/(b-a) which means that x =a +(ba) -y. The expected values and variances for the beta distribution and standard beta distribution are:Για + β) (y)-1(1-y)B-1 0

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Answered: Suppose I represents the uncertainty in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The accompanying data are x = advertising share and y = market share for a particular brand of soft drink during 10 randomly selected years. x 0.104 0.072 0.072 0.077 0.086 0.047 0.060 0.050 0.070 0.052 y 0.137 0.127 0.120 0.086 0.079 0.076 0.065 0.059 0.051 0.039 b)Calculate the equation of the estimated regression line. (Round your answers to four decimal places.) d)Calculate a point estimate of ?e. (Round your answer to five decimal places.)
The World Bank Group suggests that a minimum of 6 GB of internet data per month per user is needed for online activities to ensure better life quality (accessing news, health and educational information, social media, and other online activities). Considering the costs and poor internet connectivity, a researcher wanted to estimate the mean monthly data consumption of students in rural areas. She calculated a mean of 3.4 GB of monthly data from a random sample of 25 students. • Sub ● daia (GB) are normally disipe eviation of Complete the statement: If we consider all possible samples of the same size and a 95% confidence interval is obtained from each sample, ther ✓ [Select] Neither A nor B A. 95% of these intervals would contain 3.4 GB. Both A and B B. 5% of these intervals would not contain the true mean monthly data of students
Serum estradiol is an important risk factor for breast cancer in postmenopausal women. To better understand the etiology of breast cancer, serum-estradiol samples were collected from 25 premenopausal women (at about the same time period of the menstrual cycle) of whom 10 were Caucasian and 15 were African American. The data are shown in Table 7.3. The distribution of serum estradiol is usually highly skewed (especially for premenopausal women), and we are reluctant to assume normality. Table 7.3 Serum estradiol and ethnicity in 25 premenopausal women, where 0=Caucasian and 1=African-American. ID Serum_estradiol Ethic 1 94 0 2 54 1 3 31 0 4 21 1 5 46 1 6 56 0 7 18 1 8 19 1 9 12 1 10 14 0 11 25 0 12 35 1 13 22 1 14 71 0 15 43 1 16 35 1 17 42 1 18 50 1 19 44 1 20 41 0 21 28 0 22 65 0 23 31 0 24…
2.1 The Australian Bureau of Statistics (ABS) has recently released a report on the relationship between international students’ ethnicity and enrolments in higher education. Identify the dependent variable(s) and the independent variable (s) in the above scenario.
3. A psychologist is studying the effects of lack of sleep on the performance of various perceptual-motor tasks. After a given period of sleep deprivation, a measurement of reaction time to an auditory stimulus was taken for each of 36 adult male subjects. The reaction times (in seconds) are summarized as follows: x = 1.82, s = 0.22 Previous psychological studies show that the true mean reaction time for non-sleep- deprived male subjects is 1.70 seconds. a. Does the sample evidence indicate that the mean reaction time for sleep- deprived male subjects is longer than that of non-sleep-deprived male subjects ? a = 0.05 (iv) The conclusion for the above problem is Do not reject the null hypothesis and mean reaction time for sleep-deprived male subjects is not longer than that of non-sleep-deprived male subjects Reject the null hypothesis and mean reaction time for sleep-deprived male subjects is longer than that of non-sleep-deprived male subjects Do not reject the null hypothesis and…
2 In building electronic circuitry, the breakdown voltage of diodes is an important quality char- Acteristic. The breakdown voltage of 12 diodes were recorded as follows (in volta): 9.099 9.174 9.327 9.377 8.471 9.575 9.514 8.928 8.800 8.920 9.913 8.306 Solution A quality engineer claimed that the variability of the breakdown voltage is not less than 0.55. Can the data support the engineer's claimed at a 0.057 ii. If level of significance is reduced to 0.02, will you change the conclusions you have made in (i)? Justified your answer.
1. The data in Table 7–6 were collected in a clinical trial to evaluate a new compound designed to improve wound healing in trauma patients. The new compound was com- pared against a placebo. After treatment for 5 days with the new compound or placebo, the extent of wound healing was measured. Is there a difference in the extent of wound healing between the treatments? (Hint: Are treatment and the percent wound healing independent?) Run the appropriate test at a 5% level of significance. Use the data in Problem 1. Pool the data across the treatments into one sample of size n = 250. Use the pooled data to test whether the distribution of the percent wound healing is approximately normal. Specifically, use the following distribution 30%, 40%, 20%, and 10% and a = 0.05 to run the appropriate test. Percent Wound Healing Treatment 0-25% 26-50% 51-75% 76-100% New compound (n=125) 15 37 32 41 Placebo (n=125) 36 45 34 10
13.2.3
ASAP
5. An article in Agricultural Engineering (December 1964, pp. 672-673) described an experiment in which the daily weight gain of swine is evaluated at different levels of housing temperature. The mean weight of each group of swine at the start of the experiment is considered to be a nuisance factor. The data from this experiment are as follows: Mean Weight (lbs) Housing Air Temperatures (°F) 100 50 60 70 80 90 1.37 1.58 2.00 1.97 1.40 100 0.39 150 1.47 1.75 2.16 1.82 1.14 -0.19 200 1.19 1.91 2.22 1.67 0.88 -0.77 Does housing air temperature affect mean weight gain at a = 0.05?

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