Levi-Strauss Co manufactures clothing. The quality control department measures weekly values of different suppliers for the percentage difference of waste between the layout on the computer and the actual waste when the clothing is made (called run-up). The data is in the following table, and there are some negative values because sometimes the supplier is able to layout the pattern better than the computer ("Waste run up," 2013). Table #11.3.3: Run-ups for Different Plants Making Levi Strauss Clothing Plant 1 Plant 2 Plant 3 Plant 4 Plant 5 1.2 16.4 12.1 11.5 24 10.1 -6 9.7 10.2 -3.7 -2 -11.6 7.4 3.8 8.2 1.5 -1.3 -2.1 8.3 9.2 -3 4 10.1 6.6 -9.3 -0.7 17 4.7 10.2 8 3.2 3.8 4.6 8.8 15.8 2.7 4.3 3.9 2.7 22.3 -3.2 10.4 3.6 5.1 3.1 -1.7 4.2 9.6 11.2 16.8 2.4 8.5 9.8 5.9 11.3 0.3 6.3 6.5 13 12.3 3.5 9 5.7 6.8 16.9 -0.8 7.1 5.1 14.5 19.4 4.3 3.4 5.2 2.8 19.7 -0.8 7.3 13 3 -3.9 7.1 42.7 7.6 0.9 3.4 1.4 70.2 1.5 0.7 3 8.5 2.4 6 1.3 2.9 Do the data show that there is a difference between some of the suppliers? Test at the 1% level ********************************************************************** Let x1 = percentage difference of waste between the layout on the computer and the actual waste when the clothing is made (called run-up) from plant 1 Let x2 = percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 2 Let x3 = percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 3 Let x4 = percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 4 Let x5 = percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 5 Let μ1 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 1 Let μ2 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 2 Let μ3 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 3 Let μ4 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 4 Let μ5 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 5 (x) Comparing p-value and α value, which is the correct decision to make for this hypothesis test? A. Reject Ho B. Fail to reject Ho C. Accept Ho D. Accept HA Enter letter corresponding to correct answer. (xi) Select the statement that most correctly interprets the result of this test: A. The result is not statistically significant at .01 level of significance. Sufficient evidence exists to support the claim that there is a difference between some of the suppliers. B. The result is statistically significant at .01 level of significance. There is not enough evidence to support the claim that there is a difference between some of the suppliers. C. The result is statistically significant at .01 level of significance. Sufficient evidence exists to support the claim that there is a difference between some of the suppliers. D. The result is not statistically significant at .01 level of significance. There is not enough evidence to support the claim that there is a difference between some of the suppliers. Enter letter corresponding to most correct answer
Q9D
Levi-Strauss Co manufactures clothing. The quality control department measures weekly values of different suppliers for the percentage difference of waste between the layout on the computer and the actual waste when the clothing is made (called run-up). The data is in the following table, and there are some negative values because sometimes the supplier is able to layout the pattern better than the computer ("Waste run up," 2013).
Table #11.3.3: Run-ups for Different Plants Making Levi Strauss Clothing
|
Plant 1 |
Plant 2 |
Plant 3 |
Plant 4 |
Plant 5 |
|
1.2 |
16.4 |
12.1 |
11.5 |
24 |
|
10.1 |
-6 |
9.7 |
10.2 |
-3.7 |
|
-2 |
-11.6 |
7.4 |
3.8 |
8.2 |
|
1.5 |
-1.3 |
-2.1 |
8.3 |
9.2 |
|
-3 |
4 |
10.1 |
6.6 |
-9.3 |
|
-0.7 |
17 |
4.7 |
10.2 |
8 |
|
3.2 |
3.8 |
4.6 |
8.8 |
15.8 |
|
2.7 |
4.3 |
3.9 |
2.7 |
22.3 |
|
-3.2 |
10.4 |
3.6 |
5.1 |
3.1 |
|
-1.7 |
4.2 |
9.6 |
11.2 |
16.8 |
|
2.4 |
8.5 |
9.8 |
5.9 |
11.3 |
|
0.3 |
6.3 |
6.5 |
13 |
12.3 |
|
3.5 |
9 |
5.7 |
6.8 |
16.9 |
|
-0.8 |
7.1 |
5.1 |
14.5 |
|
|
19.4 |
4.3 |
3.4 |
5.2 |
|
|
2.8 |
19.7 |
-0.8 |
7.3 |
|
|
13 |
3 |
-3.9 |
7.1 |
|
|
42.7 |
7.6 |
0.9 |
3.4 |
|
|
1.4 |
70.2 |
1.5 |
0.7 |
|
|
3 |
8.5 |
|
|
|
|
2.4 |
6 |
|
|
|
|
1.3 |
2.9 |
|
|
|
Do the data show that there is a difference between some of the suppliers? Test at the 1% level
**********************************************************************
Let x1 = percentage difference of waste between the layout on the computer and the actual waste when the clothing is made (called run-up) from plant 1
Let x2 = percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 2
Let x3 = percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 3
Let x4 = percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 4
Let x5 = percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 5
Let μ1 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 1
Let μ2 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 2
Let μ3 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 3
Let μ4 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 4
Let μ5 = mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 5
(x) Comparing p-value and α value, which is the correct decision to make for this hypothesis test?
A. Reject Ho
B. Fail to reject Ho
C. Accept Ho
D. Accept HA
Enter letter corresponding to correct answer.
(xi) Select the statement that most correctly interprets the result of this test:
A. The result is not statistically significant at .01 level of significance. Sufficient evidence exists to support the claim that there is a difference between some of the suppliers.
B. The result is statistically significant at .01 level of significance. There is not enough evidence to support the claim that there is a difference between some of the suppliers.
C. The result is statistically significant at .01 level of significance. Sufficient evidence exists to support the claim that there is a difference between some of the suppliers.
D. The result is not statistically significant at .01 level of significance. There is not enough evidence to support the claim that there is a difference between some of the suppliers.
Enter letter corresponding to most correct answer
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
