In a study, researchers wanted to measure the effect of alcohol on the hippocampal region, the portion of the brain responsible for long-term memory storage, in adolescents. The researchers randomly selected 23 adolescents withalcohol use disorders to determine whether the hippocampal volumes in the alcoholic adolescents were less than the normal volume of 9.02 cm. An analysis of the sample data revealed that the hippocampal volume isapproximately normal with no outliers and x 8.18 cm and s=0.8 cm. Conduct the appropriate test at the a= 0.01 level of significance.State the null and alternative hypotheses.Ho: HH1:(Type integers or decimals. Do not round.)Identify the t-statistic.to = (Round to two decimal places as needed.)!!Identify the P-value.P-value = (Round to three decimal places as needed.)Make a conclusion regarding the hypothesis.the null hypothesis. Theresufficient evidence to claim that the mean hippocampal volume iscm³StatcrunchNext8:01SAMSUNGesc@%23$%&backspace13478tabW Lyme disease is an inflammatory disease that results in a skin rash and flulike symptoms. It is transmitted through the bite of an infected deer tick. The following data represent the number of reported cases of Lyme disease andthe number of drowning deaths for a rural county. Complete parts (a) through (c) below.Click the icon to view the table of Lyme disease and drowning deaths.Click the icondeia(a) Draw a scatterData tableData tableOA.ADrownings20-Critical Values for Correlation CoefficientDrowCases of Lyme DiseaseDrowningDeathsMonth3 0.9974 0.9505 0.8786 0.8117 0.7548 0.7079 0.66610 0.63211 0.60212 0.57613 0.55314 0.53215 0.51416 0.49717 0.48218 0.4680-1FLyme DiseaseLyme1(b) Determine the10The linear correlat2217(Round to three de51(c) Does a linear rs?The variables Lymvalu1(Round to three deStatcrunchNextPrintDone2.8:01SAMSUNGesc@#32$%&backspace3478.tabWety一EMAM--ASONO331022345526 544

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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I need the test statistic and p-value please and please show work and formula. Thank you! In an early Gregor Mendel’s study, he crossed two hybrid pea plants and recorded theform (round or wrinkled) and albumen color (yellow or green) of the fertilized seed. Hetheorized that these should appear in the following proportionsRound, Yellow Wrinkled, Yellow Round, Green Wrinkled, Green9/16 3/16 3/16 1/16The observed counts were as follows:Round, Yellow Wrinkled, Yellow Round, Green Wrinkled, Green Total315 101 108 32 5560. What are the expected counts?Round, Yellow Wrinkled, Yellow Round, Green Wrinkled, Green Total556Test to see if the observed counts confirm Mendel’s theory. Use ? = 0.05.1. State the null and the alternative hypothesis using the proper notation established in class. Ho:Ha:2. Is there a random sample?Are all expected counts at least 5?Proceed even if the conditions are not satisfied3. What is the significance level?How many degrees of freedom are associated with this…
Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with u = 171.7 ft and o = 91.5 ft. %3D You intend to measure a random sample of n 242 trees. What is the mean of the distribution of sample means? ft What is the standard deviation of the distribution of sample means (1.e., the standard error in estimating the mean)? (Report answer accurate to 2 decimal places.) ft Check Answer 1,299 21
refer to image
Determine the area under the standard normal curve that lies between a) 1.48 and 2.72b)-5.1 and 2.20
Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 125 adult males, the mean pulse rate is 69.7 bpm and the standard deviation is 10.6 bpm. Find the value of the test statistic, The value of the test statistic is (Round to two decimal places as needed.)
For a test of Ho-p=0.50, the sample proportion is 0.48 based on a sample size of 100 Use this information to complete parts (a) through (c) below, a. Find the test statistic z. za -04 b. Find the P.value for H p<0.50. P-valueNRound to three decimal places as needed.)
Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 149 adult males, the mean pulse rate is 67.6 bpm and the standard deviation is 10.7 bpm. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)
Pls help ASAP. Pls show all work. Pls do both of the asked questions pls i BEG.
in Find the z-scores for which 82% of the distribution's area lies between -z and z. Click to vieww page 1 of the table. Click to view page 2 of the table. ok The z-scores are nch (Use a comma to separate answers as needed. Round to two decimal places as needed.) er Contents sible Resources for Success s for Success Enter your answer in the answer box. timedia Library PrearsOIT chase Options Copvright O 2020 Pearson Education Inc All rights resenved I Terms of Use L Privacy Policy Permissi scussions DELL
The cross-tabulation data given below represent the number of males and females in a work group who feel overstressed and those who don't. Complete parts a through d below. Overstressed? Female No Yes 10 Male 5 11 a. Write the hypotheses for the chi-square test for independence. Ho gender and overstress are independent H₁ gender and overstress are dependent b. Find the expected frequencies. Overstressed? Female No Yes Grand Total 18 Male Grand Total 15 17 10 32 (Type integers or decimals rounded to two decimal places as needed.)
You are playing a dice game with a friend and become suspicious that he is using weighted dice. So you stop the game, take one of his dice, and roll it 100 times. The results are in the table below. Do these results provide significant evidence that the proportion of times the dice lands on the six numbers are unequal? Calculate the chi-squared test statistic and the range the p-value falls in for this test. Number on die 1 2 4 Frequency 16 21 6 26 13 18 test statistic = 14.12, p-value in (.01, .025) test statistic = 24.368, p-value in (.005, .01) test statistic = 14.12, p-value in (.025, 05) test statistic = 24.368, p-value less than .005 O none of these

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