Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P, the probability of A finding the electron at point A, compares to PR, the probability of finding the electron at point B.

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Chapter1: Chemical Foundations
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Ility distribution of an orbital
This sketch is about 800 pm wide.
The coordinate (x, y, and z) axes are also shown.
You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse.
IIII
Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P
finding the electron at point A, compares to P R, the probability of finding the electron at point B.
the probability of
point A
point B
compare Pa to Pg
P
100 pm in front of the nucleus, along the -y axis.
100 pm to the left of the nucleus, along the -x axis.
O P. =
O P> P
O P,<P
100 pm behind the nucleus, along the +y axis.
100 pm below the nucleus along the -z axis.
O P.= P
O P>P
O P.
100 pm to the right of the nucleus, along the +x axis.
100 pm above the nucleus, along the +z axis.
O P = P,
P> P
Explanation
Check
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Transcribed Image Text:Ility distribution of an orbital This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. IIII Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P finding the electron at point A, compares to P R, the probability of finding the electron at point B. the probability of point A point B compare Pa to Pg P 100 pm in front of the nucleus, along the -y axis. 100 pm to the left of the nucleus, along the -x axis. O P. = O P> P O P,<P 100 pm behind the nucleus, along the +y axis. 100 pm below the nucleus along the -z axis. O P.= P O P>P O P. 100 pm to the right of the nucleus, along the +x axis. 100 pm above the nucleus, along the +z axis. O P = P, P> P Explanation Check 2021 McGraw-Hill Education All Rights Reserved Terms of Use Privacy Accessibility esc
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