KSuppose a study reported that the average person watched 1.87 hours of television per day. Arandom sample of 15 people gave the number of hours of television watched per day shown.At the 5% significance level, do the data provide sufficient evidence to conclude that theamount of television watched per day last year by the average person differed from the valuereported in the study? (Note: x= 3.033 hours and s= 1.337 hours.)Ho: HHa: HThe test statistic is t=.(Round to two decimal places as needed.)Identify the critical value(s). Select the correct choice below and fill in the answer box within your choice.(Round to three decimal places as needed.)OA. The critical value is - ta =OB. The critical value is to =OC. The critical values are ±ta/2 = ±the null hypothesis. The datatelevision watched by the average person is2.23.4 3.42.1 2.5 2.36.2 2.6 1.92.2 2.8 1.72.5 4.0 5.713 №sufficient evidence to conclude that the amount ofthe value reported in the study.Time Remaining: 01:39:23Next

Answer Population mean = 1.87 Sample mean = 3.033 Standard deviation =1.337 Sample size =15 Level…

Answered: Suppose a study reported that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A sample of 250 employees of a company is selected, and the average age is found to be 35 years. This value is a statistic or parameter.
instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores: Grades 63.9 68.4 | 69 | 96 64.3 | 63.9 65 69 62.7 68.4 Test grades are believed to be normally distributed. Use a significance level of 5%. A. State the alternative hypothesis: HA: Ou + 65 Ομ 65 B. State the mean of the sample: C. State the standard error of the sample means:
On occasion, medical studies need to model the proportion of the population that has a disease and compare that to observed frequencies of the disease actually occurring. Suppose the end-stage renal failure in south-west Wales was collected for different age groups. Do the data in the table show that the observed frequencies are in agreement with proportion of people in each age group? Test at the 1% level. Renal Failure Frequencies Age group 16-29 30-44 45-59 60-74 75+ Total Observed Frequencies 125 152 134 124 48 583 Expected Proportion 0.23 0.25 0.22 0.21 0.09 State the hypotheses.H0: The observed frequencies in agreement with proportion of people in each age group.Ha: The observed frequencies in agreement with proportion of people in each age group. Calculate the χ2 test statistic. Round expected values to two decimal places. Round χ2 to 3 decimal places.χ2 = Calculate the p-value. Round to 3 decimal places.p-value = State your decision.Since p-value α,…
A hypertension trial is mounted, and 12 participants are randomly assigned to receive either a new medication or a placebo. Each participant takes the assigned medication, and the participants’ SBP is recorded after 6 months on the assigned medication. The data are shown in Table 7–9. Is there a difference in mean SBP between treatments? Run the appropriate test at a = 0.05. Placebo New Medication 134 114 143 117 148 121 142 124 150 122 160 128
A cruise ship charges passengers $3 for a can of soda. Because of passenger complaints, the ship manager has decided to try out a plan with a lower price. He thinks that with a lower price, more cans will be sold, which would mean that the ship would still make a reasonable total profit. With the old pricing, the mean number of cans sold per passenger for a 10-day trip was 10.3 cans. Suppose μ represents the mean number of cans per passenger for the new pricing. What hypotheses should the ship manager test if he wants to determine if the mean number of cans sold is greater for the new pricing plan? O Ho: μ = 10.3 versus H₂: μ> 10.3 O Ho: μ = O Ho: μ = 10 versus Ha: μ 10.3
Historically, Olympic officials have reported testosterone levels in general should be u = 538 ng/dL, with o = 189, with x being normally distributed. Summer Olympic sprinters (n = 8) from the U.S. were tested for testosterone levels the morning after the opening ceremonies. Their sample mean was ng/dL. Do these data indicate that the sprinters had an overall average testosterone level greater than 538? Use a = .05. State a, H,, H1, p-value, rejection, or non-rejection, and be certain to interpret your results.
Statistics Question
5t. A magazine reports that women trust recommendations from a particular social networking site more than recommendations from any other social network platform. But does trust in this social networking site differ by gender? The following sample data show the number of women and men who stated in a recent sample that they trust recommendations made on this particular social networking site. Women Men Sample 150 170 Trust RecommendationsMade on the social networking site 111 102 (a) What is the point estimate of the proportion of women who trust recommendations made on this particular social networking site? (b) What is the point estimate of the proportion of men who trust recommendations made on this particular social networking site? (c) Provide a 95% confidence interval estimate of the difference between the proportion of women and men who trust recommendations made on this particular social networking site. (Round your answers to four decimal places.)
An observational study of teams fishing for the red spiny lobster in a certain body of water was conducted and the results published in a science magazine. One of the variables of interest was the average distance separating traps - called "trap spacing" - deployed by the same team of fishermen. Trap spacing measurements (in meters) for a sample of seven teams of fishermen are shown in the accompanying table. Of interest is the mean trap spacing for the population of red spiny lobster fishermen fishing in this body of water. Complete parts a through f below. E Click the icon to view the trap spacing data. Trap Spacing Data a. Identify the target parameter for this study. The target parameter for this study is 93 101 107 95 81 68 84 b. Compute a point estimate of the target parameter. (Round to two decimal places as needed.) Print Done c. What is the problem with using the normal (z) statistic to finda confidence interval for the target parameter? O A. The point estimate is too large to…
Suppose you computed r=-0.524 with 20 data points. Is r significant? Explain. 0.05 significance level. Your Answer:

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