1:15(a) Describe the sampling distribution of p.A. Approximately normal, μ = 0.44 and o≈ 0.0004рр0.0157C. Approximately normal, μ = 0.44 and o≈ 0.0002pрmylab.pearson.com/+Suppose a simple random sample of size n = 1000 is obtained from a population whose size is N = 1,500,000 andwhose population proportion with a specified characteristic is p = 0.44. Complete parts (a) through (c) below.B. Approximately normal, μ = 0.44 and oрр(b) What is the probability of obtaining x = 470 or more individuals with the characteristic?P(x ≥ 470) = (Round to four decimal places as needed.)|||VO) 122 ... 46 ... - 18%=O3] :

Given: n = 1000 P = 0.44 Formula Used: μp^ = P σp^ = P(1-P)n

Answered: Suppose a simple random sample of size…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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For a sample from a normal distribution with standard deviation σσ, the standard deviation of the sampling distribution of the sample mean is σ/8σ/8. What is the size of the sample
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Suppose a simple random sample of size n = 1000 is obtained from a population whose size is N= 1,000,000 and whose population proportion with a specified characteristic is p = 0.74. Complete parts (a) through (c) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p. OA. Approximately normal, μ = 0.74 and P P OB. Approximately normal, μ = 0.74 and P P 0.0139 ≈ 0.0004 OC. Approximately normal, μ = 0.74 and ≈ 0.0002 Р (c) What is the P(x≤710) = (b) What is the probability of obtaining x = 760 or more individuals with the characteristic? P(x ≥ 760) = (Round to four decimal places as needed.) probability of obtaining x = 710 or fewer individuals with the characteristic? (Round to four decimal places as needed.)
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Suppose a simple random sample of size n = 1000 is obtained from a population whose size is N= 2,000,000 and whose population proportion with a specified characteristic is p = 0.61. Complete parts (a) through (c) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p. O A. Approximately normal, uA = 0.61 and aa z 0.0003 O B. Approximately normal, ua = 0.61 and aa 0.0002 OC. Approximately normal, ua = 0.61 and aa 0.0154 O Standard Normal Distribution Table (page 2) Aca Standard Normal Distribution 0.00 0.01 0,02 0.03 0.04 0.05 0,06 0,07 0.08 0.09 0.5000 0.5398 0.5793 0.6179 0.6554 0.5040 0.5438 0.5832 0.5080 0.5478 0.5871 0.6255 0.6628 0.5120 0.5517 0.5910 0.6293 0.6664 0.5160 0.5557 0.5948 0.6331 0.6700 0.5199 0.5596 0.5987 0.5239 0.5636 0.6026 0.6406 0.6772 0.5279 0.5675 0.6064 0.6443 0.6808 0.5319 0.5714 0.6103 0.6480 0.6844 0.5359 0.5753 0.6141 0.6517…

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