Suppose a random sample size of 60 is taken from a population with p= 0.51. The standard error of the sample proportion is %3D 0.0645 0.0495 0.0891 0.0100
Q: in a random sample of 92 trout, the average weight is 8 pounds, with standard Heviation(s) = 0.4,…
A: Answer: From the given data, Sample size(n) = 92 mean(x¯) = 8 Standard deviation(S) = 0.4
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A: Given,sample size(n)=187population proportion(P)=0.3
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A: It is given that, Confidence level =99%=0.99 n =5
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A: We have given that a researcher examines 61 critically ill patients with myxedema coma.The scenario…
Q: In a random sample of 100 trout, the average weight is 10 pounds, with standard deviation (s) = 0.6,…
A: Answer: From the given data, Sample size(n) = 100 mean (x¯) = 10 standard deviation(s) = 0.6
Q: Suppose heights, in inches, of male orangutans have an unknown distribution with mean 56 and…
A: According to the central limit theorem,
Q: Data from a representative sample were used to estimate that 31% of all computer users in a recent…
A: The preliminary estimate is, p=31%=0.31The defined margin of error is, E=0.05Since the level of…
Q: In a random sample of 80 trout, the average weight is 8 pounds, with standard deviation (s) = 0.9,…
A: Answer: From the given data, Sample size(n) = 80 mean = 8 Standard deviation(s) = 0.9
Q: A group of biologists investigated a species of worms whose length can be characterised by a normal…
A: The objective of this question is to find the length of the worms such that only 1% of the specimens…
Q: For a two-talled test at 86.12% conndence with known population variance, the critical value of the…
A: Solution : Given : Confidence level = 86.12% and population variance is known. When population…
Q: given a normal distribution curve, what is the area below a z-score of -1.2?
A: Given that, The z-score value is -1.2.
Q: Assume thAt scores on a standardized test are known to follow a bell shaped distribution with a mean…
A: L
Q: Refer to the figure at the right. At a= 0.10, can you support the claim that the proportion of women…
A: We have to find critical value.
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A:
Q: A simple random sample of 400 individuals provides 100 Yes response. What is the estimate of the…
A: We know that, If P is population proportion and p^ is sample proportion then standard error of…
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A: In statistical inference of two samples ,the margin of error is obtained by multiplying the standard…
Q: With usual notations, show that E (y,t? YN Find an %3D expression for the variance of y st
A: Answer: For the given data,
Q: normal distribution has a mean of mu = 40 with sd =5. What is the probability of sampling an…
A: we want to find probability of sampling an individual with a score greater than 48
Q: Given a normal distribution with u= 100 and o= 12, a sample mean if n= 36 is drawn at random
A: Xˉ∼N(100,2)The distribution of the sample mean Xˉ is a normal distribution with a mean of 100 and a…
Q: In a test of hypothesis, the null hypothesis is that the population variance is equal to 5.4 and the…
A: It is given that Population standard deviation = 5.4Sample standard deviation = 11.84Sample size =…
Q: Assuming a normal distribution, for a sample with M-40 and s=4, about 95% of the individuals will…
A: 32 and 48
Q: A random sample of 10 subjects have weights with a standard deviation of 12.4037 kg. What is the…
A:
Q: When simple random samples are drawn from a population that is normally distributed, the sampling…
A: According to the definition of Central limit theorem, the sampling distribution of the sample means…
Q: Construct the 90% interval estimate for the ratio of the population variances usi
A: Constructing the 90% interval estimate for the ratio of the population variances using the results…
Q: A normal distribution has a mean of u = 70 with o =3. What is the probability of sampling an…
A: We have find givan normal distribution...
Q: Suppose a simple random sample of size n=81 is obtained from a population with a mean of 88 and a…
A: Given sample of size n=81 mean=88 standard deviation =27.
Q: The sum of the squared deviation scores is SS = 20 for a sample of n = 6 scores. What is the…
A: The variance of the sample can be calculated as:
Q: A random sample of size 12 is selected from Normal distribution with mean 18 and unknown variance.…
A:
Q: SAT scores are normally distributed with a mean of 1,800 and a variance of 22,500. Given arandom…
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Q: for a normal distribution with a population mean of 74 and a standard deviation of 8, what is the…
A: given data normal distributionμ = 74σ = 8to saperate top 60% x = ?
Q: For a sample of n = 11 scores with SS = 440. What is the sample variance and the estimated standard…
A: Sample Variance s2 = SS/n-1 Estimated standard error sM = s/sqrt(n).
Q: The proportion of a population with a characteristic of interest is 0.37. A random sample of size…
A:
Q: A normal distribution has a mean of 20 and a standard deviation of 2. What is the z value of 17.5?
A:
Q: A group of biologists investigated a species of worms whose length can be characterised by a normal…
A: The objective of this question is to find the length of the worms such that only 1% of the specimens…
Q: Consider sample data with x = 24 and s = 6. (a) Compute the coefficient of variation. (b)…
A: From the provided information, x = 24 and s = 6.
Q: A normal distribution has a mean of 54, and a sttandard deviation of 6. What is the probability of…
A:
Q: The amount that households pay service providers for access to the Internet varies quite a bit, but…
A: Explanation:a sample survey asks an SRS is 500 households Find the sampling distribution of x In…
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A:
Q: In a random sample of 87 trout, the average weight is 6 pounds, with standard deviation(s) = 0.8,…
A: Answer: From the given data, Sample size(n) = 87 mean (x¯) = 6 Standard deviation(s) = 0.8
Q: Given a Normal Distribution with standard error of 11 from a population with a mean of 135 and a…
A:
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- A CNC (computer numerical control) machine produces iron automobile crankshafts. Samples are measured and the inner diameter are found to be 1.01, 0.97, 1.03, 1.04, 0.99, 0.98, 0.99, 1.01, and 1.03 centimeters. For all computations, assume an approximately normal distribution. The sample mean and standard deviation for the given data are = 1.0056, and s =0.0246. Find a 99% confidence interval on the mean of diameter. Compute a 99% prediction interval on a measured diameter of a single crankshaft piece taken from the machine. Find the 99% tolerance limits that will contain most of the metal pieces produced by the CNC machine. O a. CI on the mean: 0.9781 <µ <1.0331. Prediction Interval: 0.9186 s Xp+151.0926. Tolerance Interval (0.8937 and 1.1175) O b. Insufficient data to compute. Missing the sample size n Oc CIon the mean: 0.9781 <µ<1.0331. Prediction Interval: 0.9186 s Xp+151.0926. Tolerance Interval (0.8937 and 1.1175). Insufficient data to compute for the Tolerance Interval Od. CI on…X is a normally distributed random variable with mean 25 and standard deviation of 5. For n= 16, what is the standard error of the sampling distribution?Suppose heights, in inches, of male orangutans have an unknown distribution with mean 60 and standard deviation 3 inches. A sample of size n = 49 is randomly taken from the population and the mean is taken. Using the Central Limit Theorem for Means, what is the sample mean distribution?
- A random sample of size 21 is selected from Normal distribution with mean 12 and unknown variance. If the sample standard deviation S is 4, then the (90.)th percentile of the sample mean is closest to: a. 12.50 O b. 12.20 O c. 10.80 O d. 13.20 O e. 11.10Find x °x and Ps for all possible samples of 187 values taken from a Normally distributed population with u = 66.34 and o = 44.02 What is the mean of the population consisting of all possible sample means? %3D What is the standard deviation of the population consisting of all possible sample means? What is the variance of the population consisting of all possible sample means? %3D What is the mean of the population consisting of all possible sample variances? %3D (Round to 4 decimal places as needed) Vi (1,1) More Clear all Ask my instructorA survey of 2255 randomly selected US adults found that 51% said they know all or most of their neighbors. Find 90% CI for the proportion of US adults they know most or all their neighbors. The sample size of 200 is large enough to use a normal distribution.
- In a 4-week study about the effectiveness of using magnetic insoles to treat plantar heel pain, 58 subjects wore magnetic insoles and 40 subjects wore nonmagnetic insoles. The results are shown at the right. At a= 0.06, can you support the claim that there is a difference in the proportion of subjects who feel better between the two groups? Assume the random samples are independent. Complete parts (a) through (e). Do you Feel Better? Magnetic Insoles I Yes 20 I No 38 Nonmagnetic Insoles Yes 17 No 23 (Use a comma to separate answers as needed. Type an integer or a decimal. Round to two decimal places as needed.) Identify the rejection region(s). Select the correct choice below and fill in the answer box(es) within your choice. (Round to two decimal places as needed.) O A. z O B. z> O D. z< C. (c) Find the standardized test statistic. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis Choose the correct answer below.Jarþrúður, a geologist is working with the random variable Z that follows the standard normal distribution. What is the value of z if P (Z> z) = 0.0968?The grade point average for ALL juniors at a large college has a standard deviation of 0.50. A random sample of 20 students is to be used to estimate the population mean grade point average. What condition do you need to verify prior to computing the probability of obtaining a sample mean within plus or minus 0.2 of the population mean?
- A one-sample z-test compares a sample with 50 participants with mean 83 to a population with mean 80 and standard deviation 10. What is the effect size d? 0.1 0.3 0.5 0.7For a normally distributed random variable, the population mean is 4.32 and population standard deviation is 1.7. For a sample size of n= 21 selected randomly from the population Find the z score for sample mean x-bar= 1.6 Round to 2 decimalsAssume all populations are normally distributed. A travel analyst claims that the mean price of a round trip flight from New York City to Los Angeles is less than $507. In a random sample of 55 round trip flights from NYC to LA, the mean price is $502. Assume the population standard deviation is $111. At α = 0.05, is there enough evidence to support the travel analyst’s claim?