Suppose a recent report indicates that the mean height of girls between the ages of seven and nine is 131 cm. Rachel, a schoolnurse, collects data on a randomly selected sample of 49 girls in this age range and decides to use a hypothesis test to determinewhether the mean height is greater than reported.Which of the following hypothesis tests should Rachel use to determine if the mean height of girls between the ages ofseven and nine is greater than the reported mean of 131 cm?one-sample left-tailed z-test for a proportionone-sample right-tailed t-test for a meanone-sample two-tailed t-test for a meanone-sample right-tailed z-test for proportion

Given: Population meanμ=131Sample size(n)=49 The claim is that the height is higher than 131 cm.

Answered: Suppose a recent report indicates that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A doctor claims that the mean number of hours of sleep that seniors in high school get per night differs from the mean number of hours of sleep college seniors get per night. To investigate, he selects a random sample of 50 high school seniors from all high schools in his county. He also selects a random sample of 50 seniors from the colleges in his county. He constructs a 95% confidence interval for the true mean difference in the number of hours of sleep for seniors in high school and seniors in college. The resulting interval is (0.57, 1.25). Based upon the interval, can the doctor conclude that mean number of hours of sleep that seniors in high school get per night differs from the mean number of hours of sleep college seniors get per night? yes because 1 is in the confidence interval yes because 0 is not in the confidence interval no because 1 is in the confidence interval no because 0 is not in the confidence interval
A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 150 students in evening classes and finds that they have a mean test score of 88.8. He knows the population standard deviation for the evening classes to be 8.4 points. A random sample of 250 students from morning classes results in a mean test score of 89.9. He knows the population standard deviation for the morning classes to be 5.4 points. Test his claim with a 99% level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 3 of 3 : Draw a conclusion and interpret the decision.
A Statistics instructor wanted to compare the scores on the same final exam given to students at a local community college and local university. The Statistics instructor feels that students at the community college would be better prepared and have higher exam scores on the final exam. After grading the final exams from both institutions, the Statistics instructor found that for a sample of 36 community college students, the sample had a mean score of 84 with a standard deviation of 3.4. A sample of 45 university students had a mean score 79 with a standard deviation of 2.6. Construct a 95% confidence interval for the difference between population mean exam scores. Round your final results to one decimal place. _____________ ≤ ??? − ????? ≤ ______________
3. Of all the pupils in a particular school, 45 % go to school by bus. In a random sample of 30 pupils, calculate the mean and variance number of pupils that go to school by bus.
The average number of times Americans dine out in a week fell from 4.0 in 2008 to 3.8 in 2012 (Zagat.com, April, 2012). The number of times a sample of 20 families dined out last week provides the following data.a. Compute the mean and median.b. Compute the first and third quartiles.c. Compute the range and interquartile range.d. Compute the variance and standard deviation.e. The skewness measure for these data is 0.34. Comment on the shape of this distribution. Is it the shape you would expect? Why or why not?f. Do the data contain outliers?
Previously, an organization reported that teenagers spend 8.5 hours per week, on average, on the phone. The organization thinks that, currently, the mean is higher. Twenty-three randomly chosen teenagers were asked how many hours per week they spend on the phone, with the following results (in hours): 8.3, 8.5, 10.5, 2.9, 6.7, 7.7, 13.8, 7.8, 8.7, 11.8, 12, 6.1, 5.4, 5.8, 8.5, 7.9, 10.1,11.1, 11.6, 12.9, 3.6, 6.4, 11.2 Perform a hypothesis test using a 3% level of significance. Step 1: State the null and alternative hypotheses. Ho: ??v H: ? v ? v (So we will be performing a Select an answer v test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. v with By the Central Limit Theorem, we know that the point estimates are Select an answer and distribution standard deviation distribution mean Step 3: Find the p-value of the point estimate. P? v? v = P(| ? ♥| ? v
The mean GPA of all 45,038 students at Uneeda College is 3.21. A random sample of 50 GPAs from the school has a mean of 3.16. Is the value 3.21 a parameter or a statistic?
IS IT REASONABLE TO ASSUME THIS SAMPLE CAME FROM A NORMAL POPULATION?
Suppose that Randy is an analyst for the bicyling industry and wants to estimate the asking price of used entry-level road bikes advertised online in the southeastern part of the United States. He obtains a random sample of ?=11 online advertisements of entry-level road bikes. He determines that the mean price for these 11 bikes is ?⎯⎯⎯=$703.75 and that the sample standard deviation is ?=$189.56. He uses this information to construct a 95% confidence interval for ?, the mean price of a used road bike. a) What is the lower limit of this confidence interval? Please give your answer to the nearest cent. b) What is the upper limit of this confidence interval? Please give your answer to the nearest cent.
If sample data is such that for a one-tailed test of ? you can reject H0 at the 1% level of significance, can you always reject H0 for a two-tailed test at the same level of significance? Explain your answer? A. Yes. If H0 for a one-tailed test is rejected at the 1% level of significance, it will always be rejected for a two-tailed test at the same level of significance. B. No. If H0 for a one-tailed test is rejected at the 1% level of significance, it will never be rejected for a two-tailed test at the same level of significance. C. Yes. The P-value for the two-tailed test could be greater than 0.01. D. No. The P-value for the two-tailed test could be greater than 0.01.
Previously, an organization reported that teenagers spend 12.5 hours per week, on average, on the phone. The organization thinks that, currently, the mean is lower. Twenty-three randomly chosen teenagers were asked how many hours per week they spend on the phone, with the following results (in hours): 10.4, 10.4, 17.3, 11.2, 10, 15.2, 9.5, 5.8, 12.5, 11.8, 7.3, 10.6, 11.5, 16.2, 16.5, 14.3, 12.3, 9.9, 13.7, 8.6, 11.3, 13, 16.5 Perform a hypothesis test using a 10% level of significance. Step 1: State the null and alternative hypotheses. Ho: pv 12.5 12.5 (So we will be performing a left-tailed Vv test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are t-distributed with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. = P(tv sv p-value = Step 4: Make a Conclusion About the nulI…
The mean work week for engineers in start-up companies is claimed to be about 59 hours with a standard deviation of 6 hours. Kara, a newly hired engineer hopes that it's not (she wants it to be shorter). She asks 10 engineers in start-ups for the lengths of their mean work weeks. Their responses are 70; 45; 55; 60; 65; 55; 55; 60; 50; 55.a. Is the newly hired engineer testing a mean or a proportion? mean proportion Correct b. The null hypothesis (or company claim), in symbols, is μ=μ=Correct.c. If the claim is correct, what is the probability that a sample mean would be as low as Kara's mean?Incorrect %Give your answer as a percentage accurate to one decimal place.

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