Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: milliamperes The total amount of charge passing through the filament in t=5.00 s is: Q = coulombs Since a single electron has a charge of -1.60 x 10-19 C, the number of electrons passing through the filament in t=5.00 s is: N= x 1019 electrons

Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: milliamperes The total amount of charge passing through the filament in t=5.00 s is: Q = coulombs Since a single electron has a charge of -1.60 x 10-19 C, the number of electrons passing through the filament in t=5.00 s is: N= x 1019 electrons

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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