fill in the table with the correct answers Trial #Trial 1Trial 2Trial 3Average TimeAverageDistanceAverage SpeedTime5.50 s6.70 S6.78 sDistance23.2 m28.3 m28.7 m(T1+T2+T3) / 3 = Average Time(++)/3=s(D1+D2+D3)/3 = Average Distance(++)/3 = 6.6 m(S1+S2+S3)/3 = Average Speed(++)/3 m/sSpeedSpeed=Distance/Time23.2 M/5.50 SSpeed of trial 1=m/sSpeed=Distance/Time28.3 M/6.70 SSpeed of trial 2=m/sSpeed=Distance/Time28.7 M/6.78 SSpeed of trial 3=m/s

Name: fill in the table with the correct answers Trial #Trial 1Trial 2Trial
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: fill in the table with the correct answers Trial #Trial 1Trial 2Trial 3Average TimeAverageDistanceAverage SpeedTime5.50 s6.70 S6.78 sDistance23.2 m28.3 m28.7 m(T1+T2+T3) / 3 = Average Time(++)/3=s(D1+D2+D3)/3 = Average Distance(++)/3 = 6.6 m(S1+S2+S3

Given: For Trial 1, time is t1=5.50 s and distance is d1=23.2 m For Trial 2, time is t2=6.70 s and…

Answered: Speed | bartleby

Science

Physics

Speed

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter2: One Dimensional Motion

Section: Chapter Questions

Problem 4PQ

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Concept explainers

Displacement, Velocity and Acceleration

In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.

Linear Displacement

The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.

Topic Video

Question

fill in the table with the correct answers

Trial #
Trial 1
Trial 2
Trial 3
Average Time
Average
Distance
Average Speed
Time
5.50 s
6.70 S
6.78 s
Distance
23.2 m
28.3 m
28.7 m
(T1+T2+T3) / 3 = Average Time
(++)/3=s
(D1+D2+D3)/3 = Average Distance
(++)/3 = 6.6 m
(S1+S2+S3)/3 = Average Speed
(++)/3 m/s
Speed
Speed=
Distance/Time
23.2 M/5.50 S
Speed of trial 1
=
m/s
Speed=
Distance/Time
28.3 M/6.70 S
Speed of trial 2
=
m/s
Speed=
Distance/Time
28.7 M/6.78 S
Speed of trial 3
=
m/s

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