Support reactions using the Matrix Stiffness Analysis method. RA1SommA- 25omm²360ISomnAp 400mm-ISomRASectiun OA: 25 ommRA300setioneDA = 250 mm²* RA+30URA+300secton OA= 400mm²RA +300•SedroneGooRA+300KA- 4oommeRg= (RA+900) Total elon gation of bar = 0AAD+ Aoc +ACK + Ak8 - 0A- PLAERAXI5ORA+300) I50 (RA +900) 150(RA +300) I56250 E250 E400 E400 ERARA+ 300+RA+300RA+9002502 50400+ 2RA +3002 RA +1200250400800 RA + 120000 + SoU RA + 300000-013 00 RA +420000 =0RA = -4200001300RA - - 32 3. 076 KN (4)ThenRB= RA 1900- - 323.076 +900RB =576.924 KN (4)

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Answered: Support reactions using the Matrix…

Engineering

Civil Engineering

Support reactions using the Matrix Stiffness Analysis method.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

Support reactions using the Matrix Stiffness Analysis method.

RA
1Somm
A- 25omm²
360
ISomn
Ap 400mm-
ISom
RA
Sectiun O
A: 25 omm
RA
300
setione
D
A = 250 mm²
* RA+30U
RA+300
secton O
A= 400mm²
RA +300
•Sedrone
Goo
RA+300
K
A- 4oomme
Rg= (RA+900)

Total elon gation of bar = 0
AAD+ Aoc +ACK + Ak8 - 0
A- PL
AE
RAXI5O
RA+300) I50 (RA +900) 150
(RA +300) I56
250 E
250 E
400 E
400 E
RA
RA+ 300
+
RA+300
RA+900
250
2 50
400
+ 2RA +300
2 RA +1200
250
400
800 RA + 120000 + SoU RA + 300000-0
13 00 RA +420000 =0
RA = -420000
1300
RA - - 32 3. 076 KN (4)
Then
RB= RA 1900
- - 323.076 +900
RB =
576.924 KN (4)

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