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6-106. The bucket of the backhoe and its contents have a weight of 1200 lb and a center of gravity at G. Determine the forces of the hydraulic cylinder AB and in links AC and AD in order to hold the load in the position shown. The bucket is pinned at E. 45° 120° •G 0.25 ft 1.5 ft

6-106. The bucket of the backhoe and its contents have a weight of 1200 lb and a center of gravity at G. Determine the forces of the hydraulic cylinder AB and in links AC and AD in order to hold the load in the position shown. The bucket is pinned at E. 45° 120° •G 0.25 ft 1.5 ft

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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← _ FABC = Co2 + Cy2 = 204.375* + 245.25 = 319.24 N =319N 8:50 f fin L MENG250 - As.... Soc 501981) N T fg 694.875N T 735.75N (C) 50(9.81) N 45° 120° •G 0.25 ft 1.5 ft Dy B 1.7m 1 ft Cal 1+0₂7m+ Equations of Equilibrium: From FBD (a). (+ΣΜg = 0; 0.8m 6-106. The bucket of the backhoe and its contents have a weight of 1200 lb and a center of gravity at G. Determine the forces of the hydraulic cylinder AB and in links AC and AD in order to hold the load in the position shown. The bucket is pinned at E. 50 (9.81)N [ @ 1.6m (b) 1.2m Free Body Diagram: The solution for this problem will be simplified one realizes that the hydraulic cylinder AB, links AD and AC are two- force members. FACCOS 60° (1)+Facsin 60° (0.25) 13 14 414
Transcribed Image Text:← _ FABC = Co2 + Cy2 = 204.375* + 245.25 = 319.24 N =319N 8:50 f fin L MENG250 - As.... Soc 501981) N T fg 694.875N T 735.75N (C) 50(9.81) N 45° 120° •G 0.25 ft 1.5 ft Dy B 1.7m 1 ft Cal 1+0₂7m+ Equations of Equilibrium: From FBD (a). (+ΣΜg = 0; 0.8m 6-106. The bucket of the backhoe and its contents have a weight of 1200 lb and a center of gravity at G. Determine the forces of the hydraulic cylinder AB and in links AC and AD in order to hold the load in the position shown. The bucket is pinned at E. 50 (9.81)N [ @ 1.6m (b) 1.2m Free Body Diagram: The solution for this problem will be simplified one realizes that the hydraulic cylinder AB, links AD and AC are two- force members. FACCOS 60° (1)+Facsin 60° (0.25) 13 14 414
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