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Sulfur trioxide decomposes to form sulfur dioxide and oxygen, like this: 2 SO3(9) → 2 SO2(9) + O2(9) Also, a chemist finds that at a certain temperature the equilibrium mixture of sulfur trioxide, sulfur dioxide, and oxygen has the following composition compound concentration at equilibrium SO3 0.69 M SO2 0.83 M 02 0.95 M Calculate the value of the equilibrium constant K¸ for this reaction. Round your answer to 2 significant digits. K_ = 0

Sulfur trioxide decomposes to form sulfur dioxide and oxygen, like this: 2 SO3(9) → 2 SO2(9) + O2(9) Also, a chemist finds that at a certain temperature the equilibrium mixture of sulfur trioxide, sulfur dioxide, and oxygen has the following composition compound concentration at equilibrium SO3 0.69 M SO2 0.83 M 02 0.95 M Calculate the value of the equilibrium constant K¸ for this reaction. Round your answer to 2 significant digits. K_ = 0

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Sulfur trioxide decomposes to form sulfur dioxide and oxygen, like this: 2 SO3(9) → 2 SO2(9) + O2(9) Also, a chemist finds that at a certain temperature the equilibrium mixture of sulfur trioxide, sulfur dioxide, and oxygen has the following composition compound concentration at equilibrium SO3 0.69 M SO2 0.83 M 02 0.95 M Calculate the value of the equilibrium constant K¸ for this reaction. Round your answer to 2 significant digits. K_ = 0
Transcribed Image Text:Sulfur trioxide decomposes to form sulfur dioxide and oxygen, like this: 2 SO3(9) → 2 SO2(9) + O2(9) Also, a chemist finds that at a certain temperature the equilibrium mixture of sulfur trioxide, sulfur dioxide, and oxygen has the following composition compound concentration at equilibrium SO3 0.69 M SO2 0.83 M 02 0.95 M Calculate the value of the equilibrium constant K¸ for this reaction. Round your answer to 2 significant digits. K_ = 0
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