Sulfur trioxide decomposes at high temperature in a sealed container: 2 SO3(g) 2 SO2(g) + O2(g) Initially, the vessel is charged at 1000 K with SO3(g) at a partial pressure of 0.500 atm. At equilibrium the SO3 partial pressure is 0.200 atm. Calculate K, at 1000 K. SO3 (atm) 0.500 SO₂ (atm) 0.00 02 (atm) Initial Change Equilibrium - 2x 0.200 + 2x 2x 0.00 + X X Initial Since we're given the equilibrium partial pressure of SO3, WE THUS KNOW: 0.500 - 2x = 0.200. Therefore, x = 0.150 Fill in the table accordingly! SO3 (atm) 0.500 Change - 0.300 SO2 (atm) 0.00 + 0.300 O2 (atm) 0.00 + 0.150 Equilibrium 0.200 0.300 0.150 Thus: Kp = Ps02 P02 PS03 2 K = (0.300)2(0.150) (0.200) 2 = 0.338
Sulfur trioxide decomposes at high temperature in a sealed container: 2 SO3(g) 2 SO2(g) + O2(g) Initially, the vessel is charged at 1000 K with SO3(g) at a partial pressure of 0.500 atm. At equilibrium the SO3 partial pressure is 0.200 atm. Calculate K, at 1000 K. SO3 (atm) 0.500 SO₂ (atm) 0.00 02 (atm) Initial Change Equilibrium - 2x 0.200 + 2x 2x 0.00 + X X Initial Since we're given the equilibrium partial pressure of SO3, WE THUS KNOW: 0.500 - 2x = 0.200. Therefore, x = 0.150 Fill in the table accordingly! SO3 (atm) 0.500 Change - 0.300 SO2 (atm) 0.00 + 0.300 O2 (atm) 0.00 + 0.150 Equilibrium 0.200 0.300 0.150 Thus: Kp = Ps02 P02 PS03 2 K = (0.300)2(0.150) (0.200) 2 = 0.338
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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