Sulfur dioxide (SO₂) is a gas pollutant that is released during combustion of coal. If the partial pressure of sulfur dioxide in the air above a smoke stack is 0.05 atm and the reactions below dictate how sulfur dioxide equilibrates with water, find the equilibrium pH of a rain drop falling over the smokestack. This may be considered an OPEN system. Solve this problem using the following methods: (i) approximation with the graphical method and simple solutions; and (ii) mathematically by solving the ENE. SO2(g) → SO2 (aq) SO2 (aq) +H₂O H₂SO3 H₂SO3 H+HSO) KH = 1.23 M/atm Note, H₂SO, is the aqueous form of sulfur dioxide KA-1.26 x 10-²
Sulfur dioxide (SO₂) is a gas pollutant that is released during combustion of coal. If the partial pressure of sulfur dioxide in the air above a smoke stack is 0.05 atm and the reactions below dictate how sulfur dioxide equilibrates with water, find the equilibrium pH of a rain drop falling over the smokestack. This may be considered an OPEN system. Solve this problem using the following methods: (i) approximation with the graphical method and simple solutions; and (ii) mathematically by solving the ENE. SO2(g) → SO2 (aq) SO2 (aq) +H₂O H₂SO3 H₂SO3 H+HSO) KH = 1.23 M/atm Note, H₂SO, is the aqueous form of sulfur dioxide KA-1.26 x 10-²
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Sulfur dioxide (SO;) is a gas pollutant that is released during combustion of coal. If the partial
pressure of sulfur dioxide in the air above a smoke stack is 0.05 atm and the reactions below
dictate how sulfur dioxide equilibrates with water, find the equilibrium pH of a rain drop falling
over the smokestack. This may be considered an OPEN system. Solve this problem using the
following methods: (i) approximation with the graphical method and simple solutions; and (ii)
mathematically by solving the ENE.
SO () + SO2 (a0)
KH = 1.23 M/atm
SO: (0) + H:O → H;SO;
H;SO; + H* + HSO;
Note, H;SO, is the aqueous form of sulfur dioxide
KA = 1.26 x 10
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