Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 5.0 L flask with 2.0 atm of sulfur dioxide gas and 4.0 atm of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of sulfur trioxide gas to be 1.2 atm. Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits. X S

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You could write down the concentration equilibrium constant expression from the balanced chemical equation -- but you're not given that. You are, however,
given a description of the reaction, and you can use that to construct the chemical equation, provided you remember how to go from the names of binary
chemical
al compounds to their chemical formulae, and how to balance a chemical equation:
4NH₂(g) + 30₂ (g) — 2N₂(g) + 6H₂0 (8)
With the chemical equation you can construct the concentration equilibrium constant expression:
Nj[Hoj
K= [NH₂] [9₂]
The next step is to find the equilibrium molarities to put into this expression, and here there may seem to be a snag: you're only given the equilibrium moles of
the N₂. What about the rest of the reactants and products?
What's important here is not to forget your skills in stoichiometry when you're focused on solving equilibrium problems. Remember that if you know the change
in amount of any one reactant or product, you can solve for the change in the amounts of any other reactant or product by using the chemical equation.
For example, the rise in moles of H₂O is equal to the rise in moles of N, multiplied by the ratio of their stoichiometric coefficients:
6
change in H₂O = (change in N₂) = (3.0) = 9.000... mol
You can use relationships like this to solve for all the equilibrium moles, and then divide by the volume of the tank to get equilibrium molarities.
Another approach is to write an ICE table, even though you're not going to use it to solve a quadratic equation. Let's see what the ICE table for this reaction
looks like when you let stand for the rise in molarity of N.
Q Search
initial
change
equilibrium
0.3280
-2x
0.3280-2x
ANSWER
[NH]= 0.3280-2 (0.02400) = 0.2800.
[0₂] = 0.06000-(0.02
(0.02400)= 0.02400
[N₂] = 0.02400..
[H₂0]= 3(0.02400) = 0.07200...
(0.02400)²-(0.07200)"
(0.2800)*- (0.02400)"
X = 9.4 x 10-4
[9₂]
0.06000
0.06000*
Don't forget to round your final answer to 2 significant digits.
What's useful about this ICE table is that you already know X: you're told the equilibrium moles of N₂ is 3.0 mol, and dividing by the volume of the tank gives
you its equilibrium molarity x = 0.02400 mol/L. So if you substitute 0.02400 for x in all the expressions on the "equilibrium" line of the ICE table -- why, there
are your equilibrium molarities, ready to put into the equilibrium constant expression.
= 9.444 x 10-4
(
[N] [H₂O
0
0
x
Now you're ready substitute the equilibrium molarities into the equilibrium constant expression to find :
x
3x
3x
Remember you'll need to convert
moles to mol/L by dividing each initial
amount by the volume of the tank.
Keep a few extra digits for now, and only
round your final answer to the requested
number of significant digits.
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Transcribed Image Text:ALEKS - Harrison Felix - Learn X G Calculating an equilibrium consta X + M Gmail www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-liGOe3ZhgGhYRBIX9D1jAYn5Rlqv6WMd_eBm5plV8rDcBNiB2WKzMU7cvRstDIP55F3qFVV6qABb8cqJaFZDOQgZKWQAjqq... Q CSC-142-Java/my-a... G college proposal un... FCSC143 1VH 21801... YouTube 57°F Mostly cloudy Maps New Tab F. Home H Used ThankfulGener... You could write down the concentration equilibrium constant expression from the balanced chemical equation -- but you're not given that. You are, however, given a description of the reaction, and you can use that to construct the chemical equation, provided you remember how to go from the names of binary chemical al compounds to their chemical formulae, and how to balance a chemical equation: 4NH₂(g) + 30₂ (g) — 2N₂(g) + 6H₂0 (8) With the chemical equation you can construct the concentration equilibrium constant expression: Nj[Hoj K= [NH₂] [9₂] The next step is to find the equilibrium molarities to put into this expression, and here there may seem to be a snag: you're only given the equilibrium moles of the N₂. What about the rest of the reactants and products? What's important here is not to forget your skills in stoichiometry when you're focused on solving equilibrium problems. Remember that if you know the change in amount of any one reactant or product, you can solve for the change in the amounts of any other reactant or product by using the chemical equation. For example, the rise in moles of H₂O is equal to the rise in moles of N, multiplied by the ratio of their stoichiometric coefficients: 6 change in H₂O = (change in N₂) = (3.0) = 9.000... mol You can use relationships like this to solve for all the equilibrium moles, and then divide by the volume of the tank to get equilibrium molarities. Another approach is to write an ICE table, even though you're not going to use it to solve a quadratic equation. Let's see what the ICE table for this reaction looks like when you let stand for the rise in molarity of N. Q Search initial change equilibrium 0.3280 -2x 0.3280-2x ANSWER [NH]= 0.3280-2 (0.02400) = 0.2800. [0₂] = 0.06000-(0.02 (0.02400)= 0.02400 [N₂] = 0.02400.. [H₂0]= 3(0.02400) = 0.07200... (0.02400)²-(0.07200)" (0.2800)*- (0.02400)" X = 9.4 x 10-4 [9₂] 0.06000 0.06000* Don't forget to round your final answer to 2 significant digits. What's useful about this ICE table is that you already know X: you're told the equilibrium moles of N₂ is 3.0 mol, and dividing by the volume of the tank gives you its equilibrium molarity x = 0.02400 mol/L. So if you substitute 0.02400 for x in all the expressions on the "equilibrium" line of the ICE table -- why, there are your equilibrium molarities, ready to put into the equilibrium constant expression. = 9.444 x 10-4 ( [N] [H₂O 0 0 x Now you're ready substitute the equilibrium molarities into the equilibrium constant expression to find : x 3x 3x Remember you'll need to convert moles to mol/L by dividing each initial amount by the volume of the tank. Keep a few extra digits for now, and only round your final answer to the requested number of significant digits. H BMI Calculator Java Chapter 15 Fla... GSign in - Google Ac... 0 X Update: 11:46 AM 5/9/2023
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a
5.0 L flask with 2.0 atm of sulfur dioxide gas and 4.0 atm of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of sulfur
trioxide gas to be 1.2 atm.
Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2
significant digits.
K
P
0
x10
Transcribed Image Text:Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 5.0 L flask with 2.0 atm of sulfur dioxide gas and 4.0 atm of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of sulfur trioxide gas to be 1.2 atm. Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits. K P 0 x10
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