Styles 1. Number of oxygen molecules reacting with (68g) ammonia according to the following equation: 4NH3 + 502 -4 NO + 6 H0 Is: a) 1.9 x 1024 b) 1.2 x 1024 c) 9.5 x 1024 d) 3.0 x 1024.

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1. Number of oxygen molecules reacting with (68g) ammonia according to the
following equation:
4NH3 + 502 -4 NO+ 6 HLO
Is:
a) 1.9 x 1024
b) 1.2 x 1024
c) 9.5 x 1024
d) 3.0 x 1024.
2) For the following reaction:
N2 (g) + 3H2 (g) →2NH3 (g)
The mass of NH3 resulting from the reaction 0.25mol of H2 is:
a) 4.25g
b) 1.33g
c) 6.38g
d) 2.83g
3) If 1.2 mol of phosphorus (P) interacts with 1.2 mol of chlorine according to the
following equation:
2P + 3Cl2 → 2 PCl3
The limiting substance of the reaction:
a) Cl2
b) P
c) PCI3
d) Not one.
36°C
hp
f5
16
f7
f8
f9
f10
f11
f12
insert
सला
dele
&
backspace
6 7
80
9.
Transcribed Image Text:T Normal T No Spac. Heading 1 Heading 2 Title Font Paragraph Styles 1. Number of oxygen molecules reacting with (68g) ammonia according to the following equation: 4NH3 + 502 -4 NO+ 6 HLO Is: a) 1.9 x 1024 b) 1.2 x 1024 c) 9.5 x 1024 d) 3.0 x 1024. 2) For the following reaction: N2 (g) + 3H2 (g) →2NH3 (g) The mass of NH3 resulting from the reaction 0.25mol of H2 is: a) 4.25g b) 1.33g c) 6.38g d) 2.83g 3) If 1.2 mol of phosphorus (P) interacts with 1.2 mol of chlorine according to the following equation: 2P + 3Cl2 → 2 PCl3 The limiting substance of the reaction: a) Cl2 b) P c) PCI3 d) Not one. 36°C hp f5 16 f7 f8 f9 f10 f11 f12 insert सला dele & backspace 6 7 80 9.
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