Study the code below: public __________ ____________() { MyLinkedList newlist = new MyLinkedList<>(); for(Node ptr=head;ptr!=null;ptr=ptr.next) { newlist.prepend(ptr.element); } return newlist; } What is the purpose of the code

Study the code below: public __() { MyLinkedList newlist = new MyLinkedList<>(); for(Node ptr=head;ptr!=null;ptr=ptr.next) { newlist.prepend(ptr.element); } return newlist; } What is the purpose of the code

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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//main.cpp #include "linkedListType.h"int main(){Node* head = NULL;orderedLinkedList oll = orderedLinkedList(head); oll.insert(40);oll.insert(100);oll.insert(50); oll.printList(); oll.insert(50);oll.printList(); return 0;} //linkedListType.h #include <stdio.h>#include <iostream>using namespace std; class Node{public:int data;Node* next;}; class orderedLinkedList {Node* head; public:orderedLinkedList(Node* h) {head = h;} void insert(int new_data){Node* head_ref = head; while (head_ref != NULL && (head_ref->next != NULL) && (head_ref->next)->data < new_data){cout << head_ref->data << "\n";head_ref = head_ref->next;} if (head_ref != NULL && (head_ref->next != NULL) && (head_ref->next)->data == new_data){cout << "ERROR: Item to be inserted is already in the list\n";return;} /* Insert new node */Node* new_node = new Node();new_node->data = new_data;if (head_ref != NULL) {new_node->next =…
Create a flow chart using this code: #class for nodesclass Node:def __init__(self, data=None, link=None):self.data=dataself.link=linkdef __str__(self):return str(self.data) #class for Linked listclass LinearList:def __init__(self, start=None,nodecount=0):self.start=startself.nodecount=nodecount #stores number of nodes in linked listdef addBegNode(self, value=None):#Adding nodes at beginningnode=Node(value)node.link=self.startself.start=nodeself.nodecount=self.nodecount+1 def printList(self):#traverse add display nodesptr=self.startwhile ptr:print(ptr)ptr=ptr.linkprint()def bubblesort(self):for lst in range(self.nodecount-1): #for controlling passes of Bubble Sortcurrent=self.startnxt=current.linkprevious=Nonewhile nxt: #Comparisons in passesif current.data>nxt.data:if previous==None:previous=current.linknxt=nxt.linkprevious.link=currentcurrent.link=nxtself.start=previouselse: temp=nxtnxt=nxt.linkprevious.link=current.linkprevious=temptemp.link=currentcurrent.link=nxtelse:…
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It is python language Write the code that creates a new Node class. It will store data and next attributes. You only need to create the __init__ method. data and next variables will have default values, both set to None. Assume you are using the Node class from the previous connection to create a LinkedList. You have the code below, create a method that removes the first node from the LinkedList. class LinkedList: def __init__(self): self.head = None Based on the code from the last two questions, create a new LinkedList. Add 2 values to the LinkedList (there is an add method that accepts data as an argument, called add). Then call the removeFront method created in the previous question. Based on the previous questions, create a Queue class that uses the LinkedList for its data storage. Create the __init__, isEmpty, insert, remove, and size methods. Assume that LinkedList class has the add, removeFront and size methods defined. Based on the LinkedList code already…
In this c++ program please explain everyline of the code and explain the output. Thank you Source Code: #include <iostream>using namespace std;class Node { public: string data; Node* next; Node(string data){ this->data=data; this->next=NULL; }};class Linkedlist{ Node *head=NULL; public: Linkedlist(){ Node *head=NULL; } //addNode() will add a new node to the list void addNode(string data) { //Create a new node Node* newNode=new Node(data); //Checks if the list is empty if(head == NULL) { //If list is empty, head will point to new node head = newNode; } else if(head != NULL) { Node* temp = head; while (temp->next != NULL) { temp = temp->next; } // Insert at the last. temp->next = newNode; } } // deleteAtIndex() will delete a node at specific index void…
Assume the following method is within the SingleLinkedList class. What does it do? public void unknownMethod () { Node pt head; E temp; while (pt != null && pt.next != null) { temp pt.data; = pt.data pt.next.data; pt.next.data= temp; pt pt.next; } }
def animals(animal_dict, target): """ Filter animals based on the target category. :param animal_dict: A dictionary mapping animals to their categories. :type animal_dict: dict :param target: The target category to filter animals. :type target: str :return: A list of animals belonging to the target category. :rtype: list animals_dict = {"dogs": "mammals", "snakes": "reptiles", \ "dolphins": "mammals", "sharks": "fish"} >>> target = "mammals" >>> animals(animals_dict, target) ['dogs', 'dolphins'] >>> animals_dict = {True: "mammals"} >>> animals(animals_dict, target) # This will raise an AssertionError Traceback (most recent call last): ... AssertionError: Target should be provided and not None """ assert target is not None, "Target should be provided and not None" assert isinstance(animal_dict, dict) assert all(isinstance(animal, str) for animal in animal_dict.keys())…
my code needs help. please fix template <class T> class Node { public: /// CTORS Node() : prev_(nullptr), next_(nullptr) {} Node(T element) : element_(element), prev_(nullptr), next_(nullptr) {} Node(T element, Node *prev, Node *next) : element_(element), prev_(prev), next_(next) {} /// Set the pointer to the previous element void setPrevious(Node *prev) { prev_ = prev; } /// Set the pointer to the previous element void setPrev(Node *prev) { prev_ = prev; } /// Get a pointer to the previous element Node *getPrevious() { return prev_; } /// Get a pointer to the previous element Node *getPrev() { return prev_; } /// Set the pointer to the next node void setNext(Node *next) { next_ = next; } /// Get a pointer to the next node Node *getNext() { return next_; } /// Set the element this node holds void setElement(T element) { element_ = element; } /// Get the element this node holds T &getElement() { return element_; } /// Return a reference to the element T…
Below you're given a Node class and a LinkedList class. You will implement a method for the LinkedList class named "delete48in148". That is, whenever there is a sequence of nodes with values 1, 4, 8, we delete the 4 and 8. For exCample, Before: 1 -> 4 -> 8 LAfter: 1 Before: 7 -> 1 -> 4 -> 8 -> 9 -> 4 -> 8 After: 7 -> 1 -> 9 -> 4 -> 8 Before: 7 -> 1 -> 4 -> 8 -> 4 -> 8 -> 4 -> 8 -> 9 After: 7 -> 1 -> 9 Note from the above example that, after deleting one instance of 48, there may be new instances of 148 formed. You must delete ALL of them. Requirement: Your implementation must be ITERATIVE (i.e., using a loop). You must NOT use recursion. Recursive solutions will NOT be given marks. import ... # No other import is allowed
Given the following definition for a LinkedList: // LinkedList.h class LinkedList { public: LinkedList(); // TODO: Implement me void printEveryOther() const; private: struct Node { int data; Node* next; }; Node * head; }; // LinkedList.cpp #include "LinkedList.h" LinkedList::LinkedList() { head = nullptr; } Implement the function printEveryOther, which prints every other data value (i.e. those at the odd indices assuming 0-based indexing).
Given the following C code: atruct Node int data: struct Node previ struct Node next: Which of the following statements deletes the node pointed by X? Assume that X points to the first node of linked list and head points to the head of linked list. a) X->prev-x->next; X->next-X->prev; b) Head-X->next; Head >prev-NULL; c) Head-X->prev; X->next-NULL; d) X->prev->prev - X->prev; X->next->next-X->next;
Given the doubly linked list: head tail 10 20 30 60 40 50 assuming that the Node class has three fields: prev, info, and link, what will be the list after performing the following operations? Node temp1 Node temp2 head.setLink (templ.getLink ()); head.getLink ().getLink (); tail.getPrev () ; templ.setLink (head) ; head.setPrev (templ): head.getLink ().setPrev (head) ; templ; head temp2.setLink (templ.getPrev ()): templ.setPrev (null); tail temp2.getLink (); tail.setPrev (temp2); tail.setLink (null): O 10, 30, 40, 50 O 20, 30, 40, 50, 60 30, 10, 20, 40, 50 30, 10, 40, 50, 20 None of the above