Input code in the "Write code here" sections #include #include typedef struct node (int data;struct node nextPtr;}NODE;int addElemant (NODE **head, int item){/I Write code herevoid printlist (NODE **head) {/I Write code herevoid concatlist(NODE **1ist1, NODE **list2)(/I Write code hereint main(void)0srand(20);/1Seed fix.int num;NDDE *list[2] - (NULL);printf("How many elenenta? (8 - 188): ");scanf("d", &num):for(int ] - e; j < 2; j+)(for(int 1 - 8; 1 < num; 1++)addElenent (Elist[j), rand() S 180 + 1):for(int 1- e; i « 2; 1++)(printf("[List dl\n", 1):printList(8list[1]):concatlist (alist[@], alist[1]);printf("[Concat]\n");printList(klist[@]);return e; Create two linked lists, each of which contains five arbitrary numbers.Make concatList(NODE **list1, NODE *list2) function whichconcatenates the two lists. The concatenated list MUST be a linked list.실행 화면 예시: 공백d: 줄바꿈: 탭How many elements? (0.-.100):5J[List 0]J12.59 98 60.97.J[List 1]J82.63 42.41.82[Concat]e12.59.98 60 97 82 63.42 41 82

#include <stdio.h>#include <stdlib.h>#include <time.h> typedef struct node{ int…

#inelude stdio.h #inelude stdlib.h #inelude tine.h typedef struet nade { int data; struct node +naxtPtr; NODE; int addElement (NODE *head, int item)( I Write code here void printlist (NODE head)( I Write code here vaid concatlist(NODE *1ist1, NODE *l1st2)( I Write code here int nain(void)( srand(20); Seed fix. int num; NODE list(2] - (NULL); printf("How nany elanents? (0 - 100): "); scanf("d", anum): for(int j- 0; 1 « 2; j++){ for(int 1- 0; 1 « num; 1++) addElenent (klsst[1], rand() S 100 + 1): for(int 1- 0; 1« 2; 1++)( printf("(List a]\n", 1); printList(alist(1]): concatlist (Alist[@], alist[1]); printf("(Concat]\n"); printList(klist(0]): return e;

#inelude stdio.h #inelude stdlib.h #inelude tine.h typedef struet nade { int data; struct node +naxtPtr; NODE; int addElement (NODE head, int item)( I Write code here void printlist (NODE head)( I Write code here vaid concatlist(NODE 1ist1, NODE *l1st2)( I Write code here int nain(void)( srand(20); Seed fix. int num; NODE list(2] - (NULL); printf("How nany elanents? (0 - 100): "); scanf("d", anum): for(int j- 0; 1 « 2; j++){ for(int 1- 0; 1 « num; 1++) addElenent (klsst[1], rand() S 100 + 1): for(int 1- 0; 1« 2; 1++)( printf("(List a]\n", 1); printList(alist(1]): concatlist (Alist[@], alist[1]); printf("(Concat]\n"); printList(klist(0]): return e;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Concept of memory addresses in pointers

The concept of pointers in high-level languages was introduced in C programming. Pointers are simply the variables that are used to store memory addresses of another variable. These special variables are generally used in the languages such as C Programming and C++ Programming, where it allows the programmer to work more deeply with memory and its addresses.

Question

Input code in the "Write code here" sections

#include <stdio.h>
#include <stdlib.h
#include <tine.h>
typedef struct node (
int data;
struct node nextPtr;
}NODE;
int addElemant (NODE **head, int item){
/I Write code here
void printlist (NODE **head) {
/I Write code here
void concatlist(NODE **1ist1, NODE **list2)(
/I Write code here
int main(void)0
srand(20);/1Seed fix.
int num;
NDDE *list[2] - (NULL);
printf("How many elenenta? (8 - 188): ");
scanf("d", &num):
for(int ] - e; j < 2; j+)(
for(int 1 - 8; 1 < num; 1++)
addElenent (Elist[j), rand() S 180 + 1):
for(int 1- e; i « 2; 1++)(
printf("[List dl\n", 1):
printList(8list[1]):
concatlist (alist[@], alist[1]);
printf("[Concat]\n");
printList(klist[@]);
return e;

Create two linked lists, each of which contains five arbitrary numbers.
Make concatList(NODE **list1, NODE *list2) function which
concatenates the two lists. The concatenated list MUST be a linked list.
실행 화면 예시
: 공백
d: 줄바꿈
: 탭
How many elements? (0.-.100):5J
[List 0]J
12.59 98 60.97.J
[List 1]J
82.63 42.41.82
[Concat]e
12.59.98 60 97 82 63.42 41 82

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