Students in STA 250.899 are in progress toward a graduate degree. Does advanced education mean that you are likely to work more hours week than your less-educated co-workers? Use the GSS2014 sample.sav dataset to see if the level of education, measured by DEGREE (the IV) has an impact on the annual income of respondents, measured by EXTRAVAL (the DV). this analysis requires a one- way anova procedure
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- What source of variation is found in an ANOVA summary table for a within subjects design that is not in an ANOVA summary table for a between subjects design. What happens to this source of variation in a between-subjects design?use ms excel, thank you!A survey recently reported that the mean national annual expenditure for inpatient andoutpatient services of all persons over 64 years of age was $5,423 with a standarddeviation of $979. A random sample of 352 persons over age 64 living in Sudbury had anaverage expense of $5,516. We want to test whether the mean inpatient and outpatient expense of all Sudbury residents over age 64 is higher than the national average of $5,423. Calculate the P-value for this test.
- Is narcissism a more common personality trait today than it was a few decades ago? It is known that the mean population score on the Narcissistic Personality Inventory (NPI) for students attending University of South Alabama around 20 years ago was μ= 15 (Twenge, 2010). Interested in the narcissism levels of students in the year 2020, a researcher administers the NPI to a random sample of 25 University of Alabama sophomores this Spring term. The mean NPI score from the researcher’s sample of sophomores is M = 16.5, with s = 3.4. 1. Write the null and alternative hypotheses in symbols. Possible symbols for your answer: H0, H1, μ, M, σ. 2. Calculate the standard error. 3. Find the critical value for the test statistic, assuming alpha = .05 (Use largest [i.e., most conservative] value if exact value not given in the chart) a) 2.064 b) 1.96 c) 1.98 d) 2.000Is narcissism a more common personality trait today than it was a few decades ago? It is known that the mean population score on the Narcissistic Personality Inventory (NPI) for students attending University of South Alabama around 20 years ago was μ= 15 (Twenge, 2010). Interested in the narcissism levels of students in the year 2020, a researcher administers the NPI to a random sample of 25 University of Alabama sophomores this Spring term. The mean NPI score from the researcher’s sample of sophomores is M = 16.5, with s = 3.4. 1. Find the obtained (i.e., computed) test statistic for a sample (n=25) with a mean of 16.5 2. Make a statistical decision about the null. Will you reject or fail to reject the null based on your sample data? 3. Justify your decision about the null.Please help with d e and g only
- Watch video; https://www.youtube.com/watch?v=0YOpPVVeLaI (One-Way ANOVA) Suppose the National Transportation Safety Board wants to examine the safety of compact cars, midsize cars, and full-size cars. It collects a sample of three for each of the treatments (cars types). Using the hypothetical data provided below, test whether the mean pressure applied to the driver's head during a crash test is equal for each types of car. Use a (pvalue) = 5%. Compact cars Midsize cars Full-size cars 643 469 484 655 427 456 702 525 402 Answer below stated questions. Paste the screen shots /in excel or in other statistical program) 1. Develop the hypothesis, 2. Do the test 3. Write the result of the hypothesisWhen doing an ANOVA, you observe large differences in means between groups. Within the ANOVA framework, this would most likely be interpreted as evidence strongly favoring which hypothesis?Please provide a clear solution, 1 hour left thank you!
- A researcher notes that there seems to be a difference in the prevalence of high cholesterol among individuals who smoke and consume diets high in processed food and the prevalence of high cholesterol among individuals who do not smoke and do not consume diets high in processed foods. Use the appropriate hypothesis to determine if diet and smoking status are related (independent) at the 5%. This is the first step in determining if confounding has influenced the study’s results. Then interpret your response. Diet Low in Processed Foods Normal Cholesterol High Cholesterol Total Non-smoker 124 55 179 Smoker 69 152 221 Total 193 207 400 Diet High in Processed Foods Normal Cholesterol High Cholesterol Total Non-smoker 64 85 149 Smoker 98 153 251 Total 162 238 400 A) The chi square value of 4.65 is higher than the chi square value of 3.84, therefore we can accept H0 at the 5% level and reject…Suppose you do a small-scale study to find out whether relationship satisfaction is related to relationship status (dating, engaged, or married). You take a random sample of 39 participants, 13 of whom belong to each of the relationship status groups. You ask each participant to rate their level of satisfaction with their relationship on a 1 to 10 scale. You wish to conduct a One-Way ANOVA to test whether the differences between the groups are significant. Initial calculations reveal that the Total Sum of Squares is equal to 136.359, and the Sum of Squares for Treatments is 66.513. Find the value of the F-statistic.Suppose you do a small-scale study to find out whether relationship satisfaction is related to relationship status (dating, engaged, or married). You take a random sample of 39 participants, 13 of whom belong to each of the relationship status groups. You ask each participant to rate their level of satisfaction with their relationship on a 1 to 10 scale. You wish to conduct a One-Way ANOVA to test whether the differences between the groups are significant. Initial calculations reveal that the Total Sum of Squares is equal to 136.359, and the Sum of Squares for Treatments is 66.513. Find the value of the F-statistic.