Students in a chemistry lab are making the compound cobalt (II) carbonate. It can be made by reacting sodium carbonate solution with cobalt (II) chloride solution. Calculate the volume of 1.0 mol/L cobalt (II) chloride solution required to completely react with 250 mL of 1.5 mol/L sodium carbonate. Na2CO3(aq) + CoCl2 (aq) → COCO3(s) + 2 NaCl (aq)

Q: If 35.8 mL of 0.100 M NaOH is needed to fully react with a 100.0 mL sample of oxalic acid (H2C2O4),…

A: Given data : Molarity of NaOH = 0.100 M Volume = 35.8 mL = 0.0358 L Number of moles of…

Q: flask of 25.0 mL with an unknown concentration of magnesium hydroxide completely reacts with 18.0 mL…

A: Balanced chemical equation HCl (aq) + Mg(OH)2 (aq) -> MgCl2(aq) + H2O (l)

Q: If 31.5 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed…

A: * Answer : 57.65 grams of Cd(OH)2 will be formed in the following reaction. * Solution : Molar mass…

Q: How many liters of 0.15 M KCl solution are needed to completely react with 5.53 L of 0. 175 M lead…

A: The balanced chemical reaction is written below.2KCl (aq) + Pb(NO3)2 (aq) → PbCl2 (s) + 2KNO3…

Q: If 29.0 g of NaOH is added to 0.700 L of 1.00 M Co(NO₃)₂, how many grams of Co(OH)₂ will be formed…

A: Since ,         no of moles of CoNO32= Concentration of solution x…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.600 M Cd(NO₃)₂ reacts with 26.0 mL of…

A: Moles = Molarity x Volume in L For Cd(NO₃)₂, Molarity=0.600 M  Volume=20.5 mL= 0.0205 L Moles =0.600…

Q: A chemist adds 320.0mL of a 2.1 M calcium bromide (CaBr2) solution to a reaction flask. Calculate…

A: From the given volume and molarity of the solution, moles of calcium bromide can be calculated as

Q: Boric acid, H3BO3, is commonly used in eyewash solutions in chemistry laboratories to neutralize…

A:

Q: what mass in grams of Zn(OH)₂ will be formed

A: Number of moles = mass/molar mass  Molarity = moles/volume(in L)  Moles = molarity × volume(in L)…

Q: 60.5 mL of HNO3 is required to react with 25.0 mL of a 1.00 M Barium hydroxide solution: Find the…

A: Given- Volume of HNO3=60.5 mL  Volume of barium hydroxide= 25.0mL Molarity of barium hydroxide=…

Q: According to the following reaction, how many grams of Fe(OH)2 can form from 175.0 mL of 0.227 M…

A: The given chemical reaction is,                FeCl2(aq) + 2 NaOH(aq) →  Fe(OH)2(s) + 2 NaCl(aq)…

Q: What is the molarity of a solution of HCl if 5.50 mL of the HCl solution is titrated with 30.6 mL of…

A: Since as per the reaction, the moles of HCl reacting = moles of NaOH taken  because 1 mole of HCl is…

Q: Consider the following precipitation reaction: 2 AgNO3(aq)+ MgCl2(aq) = 2AgCl(s)+ Mg(NO3)2(aq) How…

A:

Q: Na2CO3(aq)  +  2  HCl(aq)  →   2 NaCl(aq)  +  CO2(g)  +  H2O 0.176 g of sodium carbonate required…

A:

Q: A 28.00 mL sample of an unknown HClO4 solution requires titration with 20.42 mL of 0.2100 MNaOH to…

A: The concentration of the HClO4 solution is calculated as shown in equation (1) where M(HClO4) and…

Q: When solutions of silver nitrate and magnesium chloride are mixed, silver chloride precipitates out…

A:

Q: A titration experiment required 16.64 mL of NaOH, which had a concentration of 0.135 M, to reach the…

A:

Q: A chemist prepares a solution of barium acetate (Ba(CH,CO,),) by measuring out 1.3 x 10 umol of…

A:

Q: Students in a chemistry lab are making the compound cobalt (II) carbonate. It can be made by…

A: Molarity of CoCl2 = 1.0mol/L  Volume of Na2CO3 = 250 mL  Molarity of Na2CO3 = 1.5 mol/L

Q: If 18.5 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH)₂ will be formed…

A: Given that : The mass of NaOH = 18.5 g The volume of Mn(NO₃)₂ = 0.600 L Molarity of Mn(NO₃)₂ = 1.00…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.800 M Co(NO₃)₂ reacts with 22.5 mL of…

A: Given -> Volume of Co(NO3)2 = 20.5 ml  Concentration of Co(NO3)2 = 0.800 M Volume of NaOH = 22.5…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 29.0 mL of…

A: [Cu(NO₃)₂] = 0.50 M VCu(NO₃)₂ = 20.5 ml  nCu(NO₃)₂ =  0.50 M x 20.5 ml = 10.25 m mol [NaOH ] = 0.50…

Q: A 20.0 mL sample of 0.500 M Calcium nitrate solution, Ca(NO3)2(aq), is reacted with 80.0 mL of 0.200…

A: (a) According to the question: Ca(NO3)2 = 0.500 M and 20.0 mL KIO3 = 0.200 M and 80.0 mL…

Q: What volume, in mL, of 0.339 M Li2CO3 solution is required to react with 56.4 mL of 0.332 M HNO3.

A: