Students A and B used the following steps to find the heat capacity of a sample of duralumin alloy: 1. Filled a polystyrene cup with approx. 125 g of water at temp 55°C 2. Observed the temperature of the hot water at 1 minute intervals for 8 minutes 3. Took duralumin metal sample from constant temperature vessel at approx. 20°C and submerged it in the hot water 4. Observed the temperature of the water plus duralumin at 1 minute intervals for 8 more minutes See the image below for the results.  1. in what ways was heat energy transferred in this experiment? Is it the hot water transfer heat to the alloy

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Heat transfer, Conservation of Energy question: 

Students A and B used the following steps to find the heat capacity of a sample of duralumin
alloy:
1. Filled a polystyrene cup with approx. 125 g of water at temp 55°C
2. Observed the temperature of the hot water at 1 minute intervals for 8 minutes
3. Took duralumin metal sample from constant temperature vessel at approx. 20°C and submerged
it in the hot water
4. Observed the temperature of the water plus duralumin at 1 minute intervals for 8 more minutes

See the image below for the results. 

1. in what ways was heat energy transferred in this experiment? Is it the hot water transfer heat to the alloy sample and the environment of something else? 

2. Should the data point at t=+0.5 minutes be included in the line of best fit for positive time? 

3. What were the temperature changes of the water and the alloy sample, estimate the uncertainties?

4. Find the specfic heat capacity of the duralumin alloy sample. Estimate the uncertainty in this value? Q=mcT

water specific heat = 4190 J kg-1K-1

Temperture (°C)
80
70
60
50
40
30
10
∙9 -8
5₁
S
-5 -4 -3 -2 -1
Time (mins)
O
--
IN
3
4 5 6
-
21
8 9 10
00
Transcribed Image Text:Temperture (°C) 80 70 60 50 40 30 10 ∙9 -8 5₁ S -5 -4 -3 -2 -1 Time (mins) O -- IN 3 4 5 6 - 21 8 9 10 00
The temperature data collected by Lei and Sione is given in the table below:
Time (min)
Temperature
Time (min)
Temperature
(°C)
(°C)
-8.5
56
0.5
41
-7.5
55
1.5
43
-6.5
54
2.5
43
-5.5
54
3.5
43
-4.5
53
4.5
42
-3.5
52
5.5
42
-2.5
51
6.5
42
-1.5
51
7.5
41
-0.5
50
8.5
41
Before Putting in Alloy
After Putting in Alloy!
Note that the times of the temperature observations have been shifted, so that time t = 0 min
corresponds to the time the duralumin sample was submerged in the hot water. Negative times are
before the sample was submerged; positive times are after the sample was submerged.
On the graph paper plot the temperature data and then draw two best-fit straight lines through the
data points: one for negative times and one for positive times.
Extrapolate the two straight lines to t=0 min to find the temperature of the water immediately before
and after the alloy sample is immersed. Can you estimate the uncertainty in each of these
temperatures?
Other data collected:
Mass of hot water: 134.2 g
Mass of duralumin sample: 164.8 g
Initial temperature of duralumin sample: 21.0 ± 0.1 °C
Transcribed Image Text:The temperature data collected by Lei and Sione is given in the table below: Time (min) Temperature Time (min) Temperature (°C) (°C) -8.5 56 0.5 41 -7.5 55 1.5 43 -6.5 54 2.5 43 -5.5 54 3.5 43 -4.5 53 4.5 42 -3.5 52 5.5 42 -2.5 51 6.5 42 -1.5 51 7.5 41 -0.5 50 8.5 41 Before Putting in Alloy After Putting in Alloy! Note that the times of the temperature observations have been shifted, so that time t = 0 min corresponds to the time the duralumin sample was submerged in the hot water. Negative times are before the sample was submerged; positive times are after the sample was submerged. On the graph paper plot the temperature data and then draw two best-fit straight lines through the data points: one for negative times and one for positive times. Extrapolate the two straight lines to t=0 min to find the temperature of the water immediately before and after the alloy sample is immersed. Can you estimate the uncertainty in each of these temperatures? Other data collected: Mass of hot water: 134.2 g Mass of duralumin sample: 164.8 g Initial temperature of duralumin sample: 21.0 ± 0.1 °C
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