stuck on this question, please explain your answer and each step. Thank you! Use the following evidence from a Millikan oil-drop experiment to determine the number of excess elementary charges on a charged sphere suspended between parallel plates. m = 4.2  10–15 kg V = 430 V d = 0.50 cm     3   5   20   300

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Chapter1: Units, Trigonometry. And Vectors
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stuck on this question, please explain your answer and each step. Thank you!

Use the following evidence from a Millikan oil-drop experiment to determine the number of excess elementary charges on a charged sphere suspended between parallel plates.
m = 4.2  10–15 kg
V = 430 V
d = 0.50 cm
 
 
3
 
5
 
20
 
300
Expert Solution
Step 1: INTRODUCTION

Given Data:

The mass of the charge is m equals 4.2 cross times 10 to the power of negative 15 end exponent space k g

The potential difference is V equals 430 space V

The distance between the plates is d equals 0.5 space c m equals 0.005 space m

The electric field is given by 

E equals V over d.... left parenthesis 1 right parenthesis

From oil drop experiment we get,

q E equals m g
space space space q equals fraction numerator m g over denominator E end fraction.... left parenthesis 2 right parenthesis

q is the amount of charge on the sphere.

g equals 9.81 space m over s squared, acceleration due to gravity.


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