Stock Prices A random sample of stock prices per share (in dollars) is shown. Find the 98% confidence intervals for the variance and standard deviation for the prices. Assume the variable is normally distributed. Round the sample variance and final answers to three decimal places. 46.12 10.87 40.25 60.50 28.00 28.25 6.94 45.12 13.62 53.81 <σ2< <σ<
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Stock Prices A random sample of stock prices per share (in dollars) is shown. Find the 98% confidence intervals for the variance and standard deviation for the prices. Assume the variable is
46.12
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10.87
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28.25
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6.94
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13.62
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53.81
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- Fast-Food Bills for Drive-Thru Customers A random sample of 43 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $16.14 per car. The population standard deviation is $5.51. Estimate the mean bill for all cars from the drive-thru with 97% confidence. Round intermediate and final answers to two decimal places. $ < μ < $Men Women H2 A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. 11 59 97.27°F 0.72°F n 97.68°F 0.77°F a. Use a 0.01 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? O A. Ho: H1 #H2 O B. Ho: H122 H;: H1 H2 The test statistic, t, is (Round to two decimal places as needed.)Men Women H1 H2 A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. n 11 59 97.54°F 0.78°F 97.41°F 0.64°F a. Use a 0.01 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? O A. Ho: H1 = H2 H1: H1 H2 O B. Ho: H1 =H2 H1: H1> H2 OC. Ho: H1 H2 O D. Ho: H1 2 H2 H1: H1Medical School Applications A medical college dean read that the average number of applications a potential medical school student sends is 7.7. She thinks that the mean is lower than 7.7. So she selects a random sample of 28 applicants and asks each how many medical schools they applied to. The mean of the sample is 6.8. The population standard deviation is 2.5 . Test her claim at α=0.10. Assume that the variable is normally distributed. Use the P -value method with tables. State the hypotheses and identify the claim. :H0 ▼(Choose one) :H1 ▼(Choose one) This hypothesis test is a ▼(Choose one) test. Compute the test value. Always round z score values to at least two decimal places. z= Find the P-value. Round the answer to at least four decimal places. P-value= Make the decision. ▼(Choose one) the null hypothesis. Summarize the results. There is ▼(Choose one) that the average number of applications a potential medical school…Fast-Food Bills for Drive-Thru Customers A random sample of 40 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $16.68 per car. The population standard deviation is $4.89. Estimate the mean bill for all cars from the drive-thru with 98% confidence. Round intermediate and final answers to two decimal places.Fast-Food Bills for Drive-Thru Customers A random sample of 50 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $19.19per car. The population standard deviation is $6.30. Estimate the mean bill for all cars from the drive-thru with 91% confidence. Round intermediate and final answers to two decimal places. Question $____<U< $______You have been assigned to test the hypothesis that the average mumber of hours per week that an American works is higher than the average number of hours per week that a Swede works. The following data summarizes the sample statistics for the number of hours worked per week for workers in each country. Assume normality is satisfied. Conduct an appropriate hypothesis test using a = significance. 0.05 level ofHome Ownership Rates The percentage rates of home ownership for 8 randomly selected states are listed below. Estimate the population variance and standard deviation for the percentage rate of home ownership with 98% confidence. Round the sample variance and the final answers to two decimal places. 47.2 76.8 70.3 70.2 58.4 69.5 70.4 66.6 Send data to Excel 2 <²<[ XBreaking Strength of Cable A special cable has a breaking strength of 800 pounds. The standard deviation of the population is 12 pounds. A researcher selects a sample of 23 cables and finds that the average breaking strength is 793 pounds. Can he reject the claim that the breaking strength is 800 pounds? Use the P-value method with a 0.05 level of significance. Assume that the variable is normally distributed. Use a graphing calculator. Part: 0/4 Part 1 of 4 (a) State the hypotheses and Identify the claim. Ho (Choose one) H₂: (Choose one) This hypothesis test is a (Choose one) test. 000-0 H G 民留〗f g EHome Ownership Rates The percentage rates of home ownership for 6 randomly selected states are listed below. Estimate the population variance and standard deviation for the percentage rate of home ownership with 98% confidence. Round the sample variance and the final answers to two decimal places. 71.5 72.9 69.4 73.7 73.8 69.4 Send data to Excel 2 < 0 X <0 GFreshmen GPAs First-semester GPAS for a random selection of freshmen at a large university are shown. Estimate the true mean GPA of the freshman class with 90% confidence. Assume a 0.62. Round Intermediate and final answers to two decimal places. Assume the population is normally distributed. 3.0 3.2 2.8 2.7 2.5 1.9 2.0 2.7 3.8 3.0 2.8 3.3 2.7 2.9 2.0 3.2 1.9 2.8 2.2 4.0 1.9 2.8 2.0 2.7 3.9 Send data to Excel AFWItemized Charitable Contributions The average charitable contribution itemized per income tax return in a certain state is $792. Suppose that the distribution of contributions is normal with a standard deviation of $103. Find the limits for the middle 56% of contributions. Round z-value calculations and final answers to 2 decimal places. The lower and upper limits for the middle 56% of contributions are respectively $ and $ X ŚRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. 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