**Ages of Passenger Cars**The average age of passenger train cars is 19.4 years. If the distribution of ages is normal and 18% of the cars are older than 23.5 years, find the standard deviation. Round z-value calculations to 2 decimal places and final answer to 2 decimal places.___The standard deviation must be [ ] years.[Example input box with options to submit or reset the response]

Answered: es of Passenger Cars The average age of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Ages of Passenger Cars The average age of passenger train cars is 19.4 years. If the distribution of ages is normal and 7% of the cars are older than 21.3 years, find the standard deviation. Round z-value calculations to 2 decimal places and final answer to 2 decimal places. The standard deviation must be years. X Ś
Solve the problem. Round to the nearest tenth. min one region, the September energy consumption levels for single family homes are found to be normally distributed with a mean of 1050 kWh and a standard deviation of 218 kWh. Find which is the consumption level separating the bottom 45% from the top 55%.
The amount of caffeine in a sample of five-ounce servings of brewed coffee is shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Click the icon to view the histogram. Complete the table. Round values to the nearest tenth as needed. Graph/chart f Midpoint x xf 70.5 Ay 30- 92.5 26 25- 114.5 136.5 20- 158.5 15- 12 Ef = Exf = 10- Find the mean of the data set. 5- X = (Round to the nearest tenth as needed.) 48.5 70.5 92.5 114.5 136.5 158.5 Complete the table. Round values to the nearest tenth as needed. Midpoint x (x-x)? (x-x)?f X-X 70.5 Print Done 92.5 114.5 136.5 158.5 (x-x)?r= ] of
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.481 and standard deviation a = $0.971. E Click the icon to view the frequency distribution for the tax rates. The population mean is S. (Round to three decimal places as needed.) Frequency distribution cigarette tax rates - X The population standard deviation is S (Round to three decimal places as needed.) Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2. 99 3.00-3.49 3.50-399 4.00 4.49 Frequency O Compare these results to the values found using the actual data. 14 O A. The grouped values are both slightly larger. O B. The grouped values are both slightly' smaller. O C. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller. 17 O D. The grouped mean is slightly smaller, while the…
The state and will spend 15 hours average a week and class and the standard deviation is 2 hours what percentage of students spend less than 12 hours in class
The amount of caffeine in a sample of five-ounce servings of brewed coffee is shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. W Click the icon to view the histogram. .. Complete the table. Round values to the nearest tenth as needed. Graph/chart f Midpoint x xf 70.5 Ay 30- 25- 24 20- |14 15- 10- 17 5- X 48.5 70.5 92.5 114.5 136.5 158.5
Find the range and the standard deviation (correct to two decimal places). 82, 92, 97, 97, 97 range standard deviation
The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Standard deviation CV = • 100% Mean E Click the icon to view the data sets. Data Table ..... CVneights = 71.2% (Round to the nearest tenth as needed.) Heights Weights 68 181 77 169 72 167 72 207 71 177 70 175 78 185 69 186 67 221 70 216 67 209 73 206
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 70 105 The area of the shaded region is (Round to four decimal places as needed.)
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Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P7, the 7th percentile. This is the bone density score separating the bottom 7% from the top 93%. Which graph represents P7? Choose the correct graph below. A. P7 The bone density score corresponding to P7 is (Round to two decimal places as needed.) B. A P7 2 C. ^ P7 Ly D. A P7
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