Fast-Food Bills for Drive-Thru Customers A random sample of 43 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $16.54 per car. The population standard deviation is $6.44. Estimate the mean bill for all cars from the drive-thru with 94% confidence. Round intermediate and final answers to two decimal places. <μ<$ X S
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Q: Fast-Food Bills for Drive-Thru Customers A random sample of 40 cars in the drive-thru of a popular…
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- Question Help Suppose you buy a new car whose advertised mileage is 20 miles per gallon (mpg). After driving your car for several months, you find that its mileage is 15.5 mpg. You telephone the manufacturer and learn that the standard deviation of gas mileages for all cars of the model you bought is 1.21 mpg. a. Find the z-score for the gas mileage of your car, assuming the advertised claim is correct. b. Does it appear that your car is getting unusually low gas mileage?sample sizeThe time to complete an exam is approximately Normal with a mean of 48 minutes and a standard deviation of 7 minutes. The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. Fill in the indicated boxes. H = 48 o = 7 H- 30 H-20 μ+2σ μ+ 3
- Fast-Food Bills for Drive-Thru Customers A random sample of 40 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $16.68 per car. The population standard deviation is $4.89. Estimate the mean bill for all cars from the drive-thru with 98% confidence. Round intermediate and final answers to two decimal places.Reading Improvement Program To help students improve their reading, a school district decides to implement a reading program. It is to be administered to the bottom 9% of the students in the district, based on the scores on a reading achievement exam. If the average score for the students in the district is 121.5, find the cutoff score that will make a student eligible for the program. The standard deviation is 15. Assume the variable is normally distributed. Round z-value calculations to 2 decimal places and the final answer to the nearest whole number. Cutoff score=Fast-Food Bills for Drive-Thru Customers A random sample of 50 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $19.96 per car. The population standard deviation is $4.83. Estimate the mean bill for all cars from the drive-thru with 93% confidence. Round intermediate and final answers to two decimal places. A <μFast-Food Bills for Drive-Thru Customers A random sample of 50 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $19.19per car. The population standard deviation is $6.30. Estimate the mean bill for all cars from the drive-thru with 91% confidence. Round intermediate and final answers to two decimal places. Question $____<U< $______The time to complete an exam is approximately Normal with a mean of 43 minutes and a standard deviation of 5 minutes. The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. Fill in the indicated boxes.Normal Distribution The following table shows the temperature at noon on February 21, 2018 in 5 different Canadian cities. Calculate the z-score for each temperature measurement, and find which city was experiencing the most "exceptional" (out-of-ordinary) temperature on that day. City Temp. on February 21 Average Temp. in February Std. Deviation z-score Montreal 3.4 -7.7 2.7 Toronto 3.2 -4.5 2.3 Vancouver -3.3 4.9 1.5 Regina -27 -11.7 4.2 Halifax 5.4 -5.2 2 The city with the most "exceptional" (out-of-ordinary) temperature on that day is choose: -Montreal -Toronto -Vancouver -Regina -HalifaxRound answer to 2 decimal placeMost people think that the "normal" adult body temperature is 98.6degrees°F. In a more recent study, researchers reported that a more accurate figure may be 98.198.1degrees°F. Furthermore, the standard deviation appeared to be around 0.60.6degrees°F. Assume that a Normal model is appropriate. Complete parts a through c below. Question content area bottom Part 1 a) In what interval would you expect most people's body temperatures to be? Explain. Select the correct choice below and fill in the answer box(es) to complete your choice. A. Using the 68-95-99.7 Rule, about 95% of the body temperatures are expected to be less than enter your response heredegrees°F. (Round to one decimal place as needed.) B. Using the 68-95-99.7 Rule, about 95% of the body temperatures are expected to be between enter your response heredegrees°F and enter your response heredegrees°F. (Use ascending order. Round to one decimal place as needed.) C. Using the…The time to complete an exam is approximately Normal with a mean of 45 minutes and a standard deviation of 4 minutes. The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. 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