A survey indicates that people use their computers an average of 4.5 years before buying a new one. The standard deviation is 0.75 years. Assume thedistribution is approximately normal.Find the proportion of computer users that use their computers for less than 2.5 years.Wtype your answer...SFind the proportion of computer users that use their computers more than 6.25 years.Previoustype your answer...#3Xed$54сrf%5Vt9A6bDELLyh&7On★8m9altOPctri?e+Next

GivenMean(μ)=4.5standard deviation(σ)=0.75

Answered: A survey indicates that people use…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Similar questions

Many college admissions want to know your class percentage in addition to your grades. The grades are normally distributed. A certain university insists that a student place in at the 90th percentile. if the mean is 79.45 and the standard deviation is 5.37, what is the 90th percentile? a.88.07 b.85.01 c.86.33 d.90
The lifespans of lizards in particular zoo are normally distributed. The average lizard lives 3.1 yearsthe standard deviation is 0.6 years. Find the probability that the lizards live longer than 3.1 years or less than 2.5 yearsHint: Draw and label a normal curve and use the percentages of the standard deviations. Write your answer using only numbers and do not include units. For example 95.3% would be entered as 95.3
Use the normal distribution of SAT critical reading scores for which the mean is 514 and the standard deviation is 115. Assume the variable x is normally distributed. (a) What percent of the SAT verbal scores are less than 650? (b) If 1000 SAT verbal scores are randomly selected, about how many would you expect to be greater than 550? Click to view page 1 of the standard normal table. LOADING... Click to view page 2 of the standard normal table. LOADING... Question content area bottom Part 1 (a) Approximately 1.181.18% of the SAT verbal scores are less than 650. (Round to two decimal places as needed.) Part 2 (b) You would expect that approximately 0.880.88 SAT verbal scores would be greater than 550. (Round to the nearest whole number as needed.)
The mean age of two people in a room is 20 years. A 50 year old person enters the room. What is the mean age of the 3 people in the room now 20 30 33.3 35 none of the above
Recently, a random sample of 13-18 year olds was asked, "How much do you currently have in savings?" The data in the table represent the responses to the survey. Approximate the mean and standard deviation amount of savings. Click the icon to view the frequency distribution for the amount of savings. The sample mean amount of savings is $ (Round to the nearest dollar as needed.) Frequency distribution of amount of savings Savings $0-$199 $200-$399 $400-$599 $600-$799 $800-$999 $1000-$1199 $1200-$1399 Print Frequency 338 97 50 25 10 7 3 Done X
A distribution has mean 100 and standard deviation 3. What is the largest percent of the data that is guaranteed to be between 40 and 160 93.75 96 97.44 99.75 99.99
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P9, the 9th percentile. This is the bone density score separating the bottom 9% from the top 91%. Which graph represents P9? Choose the correct graph below.
It has been reported that 84% of federal government employees use e- mail. If a sample of 235 federal government employees is selected, find the mean, variance, and standard deviation of the number who use e-mail. Round your answers to three decimal places. a. Find mean
Students in a class took a test whose results were normally distributed. The mean score was an 81 and the standard deviation was 4.5. What score is at the 83rd percentile (round to the nearest whole number.) a.84 b.83 c.85 d.86
In a certain population, the mean score on a test is 420. The standard deviation is 105. If the distribution or scores is normal, which of these scores should occur most often. a. 385 b314 c. 540 d. 526
Recently, a random sample of 13–18 year olds was asked, "How much do you currently have in savings?" The data in the table represent the responses to the survey. Approximate the mean and standard deviation amount of savings. LOADING... Click the icon to view the frequency distribution for the amount of savings. Savings Frequency $0– $199 343 $200– $399 94 $400– $599 62 $600– $799 21 $800– $999 9 $1000– $1199 5 $1200– $1399 3 The sample mean amount of savings is $nothing. (Round to the nearest dollar as needed.) The sample standard deviation is $nothing. (Round to the nearest dollar as needed.)

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