Carbohydrates
Carbohydrates are the organic compounds that are obtained in foods and living matters in the shape of sugars, cellulose, and starch. The general formula of carbohydrates is Cn(H2O)2. The ratio of H and O present in carbohydrates is identical to water.
Starch
Starch is a polysaccharide carbohydrate that belongs to the category of polysaccharide carbohydrates.
Mutarotation
The rotation of a particular structure of the chiral compound because of the epimerization is called mutarotation. It is the repercussion of the ring chain tautomerism. In terms of glucose, this can be defined as the modification in the equilibrium of the α- and β- glucose anomers upon its dissolution in the solvent water. This process is usually seen in the chemistry of carbohydrates.
L Sugar
A chemical compound that is represented with a molecular formula C6H12O6 is called L-(-) sugar. At the carbon’s 5th position, the hydroxyl group is placed to the compound’s left and therefore the sugar is represented as L(-)-sugar. It is capable of rotating the polarized light’s plane in the direction anticlockwise. L isomers are one of the 2 isomers formed by the configurational stereochemistry of the carbohydrates.
For the reactions below, predict the products and indicate the major product.
![**Chemical Reactions for Synthesis**
1. **Steroid Backbone Formation:**
- **Reactants:**
- A polycyclic aromatic compound with a methoxy group and two ring structures.
- A cyclic compound with a ketone group.
- **Reaction:** These reactants combine to form a complex steroid backbone structure.
2. **Alkyne Formation Reaction:**
- **Reactants:**
- An alkene (shown as a simple structure with a carbon-carbon double bond on a straight chain).
- A benzene ring with an acetylene group (HC≡C).
- **Reaction:** These reactants undergo a chemical transformation to form a new compound. The specifics of the final product are not detailed in the diagram.
These reactions illustrate key steps in organic synthesis, showing how basic chemical structures are used to create more complex molecules.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd21fe99f-4b35-4dba-8417-03a5b613362f%2Fd8901215-49da-421f-809d-fd55d3079e48%2Fek1dj1zp_processed.jpeg&w=3840&q=75)
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