会云* 00TFLRIn a poll, 37% of the people polled answered yes to the question "Are you in favor of the death penalty for a person convicted of murder?" The margin oferror in the poll was 2%, and the estimate was made with 96% confidence. At least how many people were surveyed?Click here to view the standard normal distribution table (page 1).Click here to view the standard normal distribution table (page 2).The minimum number of surveyed people was 2458. (Round up to the nearest integer.)NextDECétvMacBook AirDDF708F8F4F5F2V%2324264.9-KS1

Answered: Image /qna-images/answer/6baefb84-2001-4e3b-a87a-9b94b4738dd6.jpg

Answered: 会云 * 00 T FL R In a poll, 37% of the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the standard normal distribution table to determine the percent of data between z= 1.06 and z= 1.53. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. O ..... The percent of data between z = 1.06 and z = 1.53 is (Round to two decimal places as needed.) %. %3D in ms Clear all Check answer Get more help- here to search
According to a study, the proportion of people who are satisfied with the way things are going in their lives is 0.86. Suppose that a random sample of 100 people is obtained. Complete parts (a) through (e) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). O A. The response is qualitative because the number of people satisfied can be counted. O B. The response is quantitative because the number of people satisfied can be counted. O C. The response is quantitative because the responses can be classified based on the characteristic of being satisfied or not. YD. The response is qualitative because the responses can be classified based on the characteristic of being satisfied or not. (b) Explain why the sample proportion, p, is a random variable. What is the source of the variability? The sample proportion p is a random variable because the value of p represents a random person included in the…
In a bell-shaped, normal distribution, a. mode = 0 b. median > mean c. median < mean d. median = mean
According to a survey in a country, 32% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because n <0.05N and np(1 – p)< 10 GB. Approximately normal because n<0.05N and np(1 - p) 2 10 CC. Not normal because ns0.05N and np(1 - p) 2 10 D. Approximately normal because n<0.05N and np(1 - p)< 10 Determine the mean of the sampling distribution of p. (Round to two decimal places as needed.) p Enter your answer in the answer box and then click Check Answer. ? 6. parts remaining Clear All Check Answer
The height of women ages 20-29 is normally distributed, with a mean of 64.9 inches. Assume a = 2.5 inches. Are you more likely to randomly select 1 woman with a height less than 65.8 inches or are you more likely to select a sample of 29 women with a mean height less than 65.8 inches? Explain. E Click the icon to view page 1 of the standard normal table. E Click the icon to view page 2 of the standard normal table, What is the probability of randomly selecting 1 woman with a height less than 65.8 inches? O (Round to four decimal places as needed.)
For a recent 10k run, the finishers are normally distributed with mean 63 minutes and standard deviation 10 minutes. Complete parts (a) through (d) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. Determine the percentage of finishers with times between 45 and 75 minutes. Approximately 84.9 % of finishers had times between 45 and 75 minutes. (Round to two decimal places as needed.) b. Determine the percentage of finishers with times less than 80 minutes. Approximately 95.54 % of finishers had times less than 80 minutes. (Round to two decimal places as needed.) c. Obtain and interpret the 35th percentile for the finishing times. The 35th percentile is minutes. (Round to two decimal places as needed.)
The graph of the normal distribution resembles a "bell" curve. True SAMSUNG & False C $ % * 0
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a.What decision can you make? b. What does that decision mean? c. What type of error could you be making, and what would it mean?
In a survey, 39% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result to be too high, so she randomly selected 160 pet owners and discovered that 56 of them spoke to their pet on the telephone. Does the veterinarian have a right to be skeptical? Use the a = 0.05 level of significance. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Because npo (1-po) =U V10, the sample size is V 5% of the population size, and the sample the requirements for testing the hypothesis satisfied, (Round to one decimal place as needed.) What are the null and alternative hypotheses? V versus H,: (Type integers or decimals. Do not round.) Но Determine the test statistic, zo Zo = |(Round to two decimal places as needed.) Determine the critical value(s). Select the correct choice below and fill in the answer box to complete your choice. (Round to two decimal places as…
In a survey, 34% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result to be too high, so he randomly selected 210 pet owners and discovered that 70 of them spoke to their pet on the telephone. Does the veterinarian have a right to be skeptical? Use the a = 0.05 level of significance. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Because npo (1- Po): V 10, the sample size is V 5% of the population size, and the sample the requirements for testing the hypothesis satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? versus H: Ho: (Type integers or decimals. Do not round.) Determine the test statistic, Zo Z0 = (Round to two decimal places as needed.) Determine the critical value(s). Select the correct choice below and fill in the answer box to complete your choice. (Round to two decimal places as…
In a recent poll, 45% of survey respondents said that, if they only had one child, they would prefer the child to be a boy. Suppose you conducted a survey of 160 randomly selected students on your campus and find that 79 of them would prefer a boy. Complete parts (a) and (b) below. Click here to view the standard normal distribution table (page 1). LOADING... Click here to view the standard normal distribution table (page 2). LOADING... (a) Use the normal approximation to the binomial to approximate the probability that, in a random sample of 160 students, at least 79 would prefer a boy, assuming the true percentage is 45%. The probability that at least 79 students would prefer a boy is 3636. (Round to four decimal places as needed.)

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