## Standard Normal Distribution Table### OverviewThis table is used to find the probability that a statistic is observed below, above, or between values on the standard normal distribution. The table is divided into two pages to provide a detailed lookup for various z-scores.### Explanation of GraphsBoth pages contain a small diagram depicting a standard normal curve (bell-shaped curve). - **Page 1 and Page 2 Diagrams**: - The horizontal axis is labeled with "z," representing z-scores. - The shaded area under the curve indicates the probability associated with a particular z-score. - The arrow labeled "Area" points to the shaded region, illustrating the cumulative probability for z-values up to the marked point.### Standard Normal Distribution Table (Page 1)This page lists cumulative probabilities for z-scores ranging from -3.4 to -0.1.**Table Structure:**- The leftmost column shows z-scores (e.g., -3.4, -3.3, ..., -0.1).- The top row contains decimal place values from 0.00 to 0.09.- For each z-score, the corresponding cumulative probabilities are listed across the row at 0.01 intervals.### Standard Normal Distribution Table (Page 2)This page continues the table, listing cumulative probabilities for z-scores ranging from 0.0 to 3.8.**Table Structure:**- The leftmost column shows z-scores (e.g., 0.0, 0.1, ..., 3.8).- The top row contains decimal place values from 0.00 to 0.09.- For each z-score, the cumulative probabilities are listed across the row at 0.01 intervals.### UsageThese tables are used to determine the percentile rank of a standard normal variable, helpful in various statistical analyses, including hypothesis testing and confidence interval estimation. By finding the intersection of a z-score and its corresponding column value, you can determine the probability of a statistic falling within a certain range. According to a survey in a country, 35% of adults do not own a credit card. Suppose a simple random sample of 700 adults is obtained. Complete parts (a) through (d) below.**(a) Describe the sampling distribution of $ \hat{p} $, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of $ \hat{p} $ below.**- **A.** Approximately normal because $ n \leq 0.05N $ and $ np(1 - p) < 10 $- **B.** Not normal because $ n \leq 0.05N $ and $ np(1 - p) \geq 10 $- **C.** Not normal because $ n \leq 0.05N $ and $ np(1 - p) < 10 $- **D.** Approximately normal because $ n \leq 0.05N $ and $ np(1 - p) \geq 10 $There are no graphs or diagrams in the image. The task involves selecting an option that correctly describes the sampling distribution based on the given conditions related to sample size and the calculated product of $ np(1 - p) $.

(a) The sample size is 700 and proportion is 35%. That is, n=700,p=0.35.

Answered: According to a survey in a country, 35%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to the Carnegie unit system, the recommended number of hours students should study per unit is 2. Are statistics students' study hours more than the recommended number of hours per unit? The data show the results of a survey of 15 statistics students who were asked how many hours per unit they studied. Assume a normal distribution for the population. 0.7, 4.1, 0.6, 4.4, 3.2, 0.8, 3.1, 3.8, 1.1, 3.3, 2.1, 1.5, 2.5, 2.3, 1.7 What can be concluded at the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean study time per unit for statistics students is not significantly more…
What is a skewed distribution?
According to a survey in a country, 21% of adults do not own a credit card. Suppose a simple random sample of 200 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1 - p) 2 10 B. Approximately normal because ns0.05N and np(1 - p) 2 10 O C. Not normal because ns0.05N and np(1 - p) < 10 O D. Approximately normal because ns0.05N and np(1- p) < 10 Determine the mean of the sampling distribution of p. HA = 0.21 (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. On = 0.029 (Round to three decimal places as needed.) (b) What is the probability that in a random…
Sample Size. How does the sample size affect how close to a normal distribution of either sample means or sample proportion will be?
According to the Carnegie unit system, the recommended number of hours students should study per unit is 2. Are statistics students' study hours more than the recommended number of hours per unit? The data show the results of a survey of 11 statistics students who were asked how many hours per unit they studied. Assume a normal distribution for the population. 2, 2.9, 4.5, 0.7, 3.3, 4.5, 4.2, 1.2, 0.9, 1.8, 2.8 What can be concluded at the αα = 0.05 level of significance? The p-value = (Please show your answer to 4 decimal places. Based on this, we should Select an answer fail to reject accept reject the null hypothesis Thus, the final conclusion is that ... The data suggest the populaton mean is significantly more than 2 at αα = 0.05, so there is enough evidence to conclude that the population mean study time per unit for statistics students is more than 2. The data suggest the population mean is not significantly more than 2 at αα = 0.05, so there is enough evidence to…
A developmental psychologist is interested in studying how long babies gaze at a photograph of a human face. To test this question, she shows a picture to a sample of six babies and records the length of their gaze in seconds. The data are as follows: 12, 17, 18, 20, 20, 29. Calculate the mean, median, mode, range, variance and standard deviation for the sample.
1. Comment on the shape of the distribution. 2. Use the empirical rule to state the percentage of annual sales between 1255 and 9181(millions of dollars) 3. Based on the z score, is the highest sale, $14138 (in millions) an outlier? Explain
According to a survey in a country, 32% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because n <0.05N and np(1 – p)< 10 GB. Approximately normal because n<0.05N and np(1 - p) 2 10 CC. Not normal because ns0.05N and np(1 - p) 2 10 D. Approximately normal because n<0.05N and np(1 - p)< 10 Determine the mean of the sampling distribution of p. (Round to two decimal places as needed.) p Enter your answer in the answer box and then click Check Answer. ? 6. parts remaining Clear All Check Answer
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The average final exam score for the statistics course is 43%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is larger. The final exam scores for the 19 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 54, 38, 45, 47, 42, 42, 48, 38, 56, 51, 46, 41, 43, 41, 37, 40, 53, 43, 43 Copy to clipboard What can be concluded at the = 0.05 level of the significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer H1: ? Select an answer c. The test statistic ? v (please show your answer to 3 decimal places.)
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