According to a survey in a country, 23% of adults do not own a credit card. Suppose a simple random sample of 800 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). LOADING... Click here to view the standard normal distribution table (page 2). LOADING... (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. A. Not normal because n≤0.05N and np(1−p)≥10 B. Approximately normal because n≤0.05N and np(1−p)<10 C. Approximately normal because n≤0.05N and np(1−p)≥10 D. Not normal because n≤0.05N and np(1−p)<10 Determine the mean of the sampling distribution of p. μp=nothing (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p.
According to a survey in a country, 23% of adults do not own a credit card. Suppose a simple random sample of 800 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). LOADING... Click here to view the standard normal distribution table (page 2). LOADING... (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. A. Not normal because n≤0.05N and np(1−p)≥10 B. Approximately normal because n≤0.05N and np(1−p)<10 C. Approximately normal because n≤0.05N and np(1−p)≥10 D. Not normal because n≤0.05N and np(1−p)<10 Determine the mean of the sampling distribution of p. μp=nothing (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
100%
According to a survey in a country,
23%
of adults do not own a credit card. Suppose a simple random sample of
800
adults is obtained. Complete parts (a) through (d) below.Click here to view the standard normal distribution table (page 1).
LOADING...
Click here to view the standard normal distribution table (page 2).
LOADING...
(a) Describe the sampling distribution of
p,
the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of
p
below.Not normal because
n≤0.05N
and np(1−p)≥10Approximately normal because
n≤0.05N
and np(1−p)<10Approximately normal because
n≤0.05N
and np(1−p)≥10Not normal because
n≤0.05N
and np(1−p)<10Determine the mean of the sampling distribution of
p.
μp=nothing
(Round to two decimal places as needed.)Determine the standard deviation of the sampling distribution of
p.
σp=nothing
(Round to three decimal places as needed.)(b) What is the probability that in a random sample of
800
adults, more than
24%
do not own a credit card?The probability is
nothing.
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of
800
adults were obtained, one would expect
nothing
to result in more than
24%
not owning a credit card.(Round to the nearest integer as needed.)
(c) What is the probability that in a random sample of
800
adults, between
19%
and
24%
do not own a credit card?The probability is
nothing.
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of
800
adults were obtained, one would expect
nothing
to result in between
19%
and
24%
not owning a credit card.(Round to the nearest integer as needed.)
(d) Would it be unusual for a random sample of
800
adults to result in
152
or fewer who do not own a credit card? Why? Select the correct choice below and fill in the answer box to complete your choice.(Round to four decimal places as needed.)
The result
is
unusual because the probability that
p
is less than or equal to the sample proportion is
nothing,
which is
less
than 5%.The result
is not
unusual because the probability that
p
is less than or equal to the sample proportion is
nothing,
which is
less
than 5%.The result
is not
unusual because the probability that
p
is less than or equal to the sample proportion is
nothing,
which is
greater
than 5%.The result
is
unusual because the probability that
p
is less than or equal to the sample proportion is
nothing,
which is
greater
than 5%.Expert Solution
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