According to a survey in a country, 21% of adults do not own a credit card. Suppose a simple random sample of 200 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p)2 10 B. Approximately normal because ns0.05N and np(1-p) 2 10 O C. Not normal because ns0.05N and np(1- p) < 10 O D. Approximately normal because ns0.05N and np(1-p)< 10 Determine the mean of the sampling distribution of p. Ha = 0.21 (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. On = 0.029 (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 200 adults, more than 25% do not own a credit card? The probability is 0.0838 (Round to four decimal places as needed.) Interpret this probability. If 100 different random samples of 200 adults were obtained, one would expect 8 to result in more than 25% not owning a credit card. (Round to the nearest integer as needed.) (c) What is the probability that in a random sample of 200 adults, between 20% and 25% do not own a credit card? The probability is 0.5493 (Round to four decimal places as needed.) Interpret this probability. to result in between 20% and 25% not owning a credit card. If 100 different random samples of 200 adults were obtained, one would expect (Round to the nearest integer as needed.)
According to a survey in a country, 21% of adults do not own a credit card. Suppose a simple random sample of 200 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p)2 10 B. Approximately normal because ns0.05N and np(1-p) 2 10 O C. Not normal because ns0.05N and np(1- p) < 10 O D. Approximately normal because ns0.05N and np(1-p)< 10 Determine the mean of the sampling distribution of p. Ha = 0.21 (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. On = 0.029 (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 200 adults, more than 25% do not own a credit card? The probability is 0.0838 (Round to four decimal places as needed.) Interpret this probability. If 100 different random samples of 200 adults were obtained, one would expect 8 to result in more than 25% not owning a credit card. (Round to the nearest integer as needed.) (c) What is the probability that in a random sample of 200 adults, between 20% and 25% do not own a credit card? The probability is 0.5493 (Round to four decimal places as needed.) Interpret this probability. to result in between 20% and 25% not owning a credit card. If 100 different random samples of 200 adults were obtained, one would expect (Round to the nearest integer as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Continuous Probability Distributions
Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could count from 0 to a trillion seconds, billion seconds, so on indefinitely. A discrete probability distribution consists of only a countable set of possible values.
Normal Distribution
Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a great idea as the sensitivity of the scale would get reduced if the range is too large. At the same time, if we keep the upper limit too low, it may not be usable for a large percentage of the population!
Question
Transcribed Image Text:According to a survey in a country, 21% of adults do not own a credit card. Suppose a simple random sample of 200 adults is obtained. Complete parts (a) through (d) below.
Click here to view the standard normal distribution table (page 1).
Click here to view the standard normal distribution table (page 2).
(a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below.
O A. Not normal because ns0.05N and np(1 - p) 2 10
B. Approximately normal because ns0.05N and np(1 - p) 2 10
O C. Not normal because ns0.05N and np(1 - p) < 10
O D. Approximately normal because ns0.05N and np(1- p) < 10
Determine the mean of the sampling distribution of p.
HA = 0.21 (Round to two decimal places as needed.)
Determine the standard deviation of the sampling distribution of p.
On = 0.029 (Round to three decimal places as needed.)
(b) What is the probability that in a random sample of 200 adults, more than 25% do not own a credit card?
The probability is 0.0838.
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 200 adults were obtained, one would expect 8 to result in more than 25% not owning a credit card.
(Round to the nearest integer as needed.)
(c) What is the probability that in a random sample of 200 adults, between 20% and 25% do not own a credit card?
The probability is 0.5493.
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 200 adults were obtained, one would expect
to result in between 20% and 25% not owning a credit card.
(Round to the nearest integer as needed.)
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