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PiXx) ,18 44 .27 ,08 L03 10 MeaN 0324 ,1936 .0729 44 54 24 12 1.34 3. 306 T,31-(134 .31 131- SD= 1,34 1:00 ,9615 VALANCO 7-1.49 2.2 9- A Bank of America VP feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. # Cards, X 0. 1 3 Probability of X 0.18 0.44 0.27 0.08 0.03 a. Find the mean and standard deviation. MEAN-I.3 Y, SD=2.2 b. Is the VP correct in her assumption? NO

PiXx) ,18 44 .27 ,08 L03 10 MeaN 0324 ,1936 .0729 44 54 24 12 1.34 3. 306 T,31-(134 .31 131- SD= 1,34 1:00 ,9615 VALANCO 7-1.49 2.2 9- A Bank of America VP feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. # Cards, X 0. 1 3 Probability of X 0.18 0.44 0.27 0.08 0.03 a. Find the mean and standard deviation. MEAN-I.3 Y, SD=2.2 b. Is the VP correct in her assumption? NO

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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PiXx) ,18 44 .27 ,08 L03 10 MeaN 0324 ,1936 .0729 44 54 24 12 1.34 3. 306 T,31-(134 .31 131- SD= 1,34 1:00 ,9615 VALANCO 7-1.49 2.2 9-
Transcribed Image Text:PiXx) ,18 44 .27 ,08 L03 10 MeaN 0324 ,1936 .0729 44 54 24 12 1.34 3. 306 T,31-(134 .31 131- SD= 1,34 1:00 ,9615 VALANCO 7-1.49 2.2 9-
A Bank of America VP feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. # Cards, X 0. 1 3 Probability of X 0.18 0.44 0.27 0.08 0.03 a. Find the mean and standard deviation. MEAN-I.3 Y, SD=2.2 b. Is the VP correct in her assumption? NO
Transcribed Image Text:A Bank of America VP feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. # Cards, X 0. 1 3 Probability of X 0.18 0.44 0.27 0.08 0.03 a. Find the mean and standard deviation. MEAN-I.3 Y, SD=2.2 b. Is the VP correct in her assumption? NO
Expert Solution
Step 1

Given the distribution represents the number of credit cards people own:

X 0 1 2 3 4
P(X) 0.18 0.44 0.27 0.08 0.03

We need to calculate  the Mean and standard deviation.

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