PiXx) ,18 44 .27 ,08 L03 10 MeaN 0324 ,1936 .0729 44 54 24 12 1.34 3. 306 T,31-(134 .31 131- SD= 1,34 1:00 ,9615 VALANCO 7-1.49 2.2 9- A Bank of America VP feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. # Cards, X 0. 1 3 Probability of X 0.18 0.44 0.27 0.08 0.03 a. Find the mean and standard deviation. MEAN-I.3 Y, SD=2.2 b. Is the VP correct in her assumption? NO
PiXx) ,18 44 .27 ,08 L03 10 MeaN 0324 ,1936 .0729 44 54 24 12 1.34 3. 306 T,31-(134 .31 131- SD= 1,34 1:00 ,9615 VALANCO 7-1.49 2.2 9- A Bank of America VP feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. # Cards, X 0. 1 3 Probability of X 0.18 0.44 0.27 0.08 0.03 a. Find the mean and standard deviation. MEAN-I.3 Y, SD=2.2 b. Is the VP correct in her assumption? NO
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
I feel lik I did something wrong here, but I am not sure where. Can someone help me find my mistake?
![PiXx)
,18
44
.27
,08
L03
10
MeaN
0324
,1936
.0729
44
54
24
12
1.34
3.
306
T,31-(134
.31
131-
SD=
1,34
1:00
,9615
VALANCO
7-1.49
2.2
9-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b8f0e9b-4191-4510-a02c-e23c76532d1a%2F368c1c3b-6e02-455f-91b4-4637ea6193ea%2F1n4x3wk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:PiXx)
,18
44
.27
,08
L03
10
MeaN
0324
,1936
.0729
44
54
24
12
1.34
3.
306
T,31-(134
.31
131-
SD=
1,34
1:00
,9615
VALANCO
7-1.49
2.2
9-
![A Bank of America VP feels that each savings account customer has, on average, three credit cards. The
following distribution represents the number of credit cards people own.
# Cards, X
0.
1
3
Probability of X
0.18
0.44
0.27
0.08
0.03
a.
Find the mean and standard deviation.
MEAN-I.3
Y,
SD=2.2
b. Is the VP correct in her assumption?
NO](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b8f0e9b-4191-4510-a02c-e23c76532d1a%2F368c1c3b-6e02-455f-91b4-4637ea6193ea%2Fc9bn1wk.jpeg&w=3840&q=75)
Transcribed Image Text:A Bank of America VP feels that each savings account customer has, on average, three credit cards. The
following distribution represents the number of credit cards people own.
# Cards, X
0.
1
3
Probability of X
0.18
0.44
0.27
0.08
0.03
a.
Find the mean and standard deviation.
MEAN-I.3
Y,
SD=2.2
b. Is the VP correct in her assumption?
NO
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given the distribution represents the number of credit cards people own:
X | 0 | 1 | 2 | 3 | 4 |
P(X) | 0.18 | 0.44 | 0.27 | 0.08 | 0.03 |
We need to calculate the Mean and standard deviation.
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