### Lesson 2.1 Frequency Distributions **Instruction Step: 1 of 2** #### Frequency Distribution Table Below is a frequency table representing the distribution of the length of screws (in inches). | Class Length (in inches) | Frequency | |--------------------------|-----------| | 0.28–0.37 | 13 | | 0.38–0.47 | 12 | | 0.48–0.57 | 9 | | 0.58–0.67 | 6 | | 0.68–0.77 | 13 | **Task:** Determine the midpoint for the second class. To find the midpoint of a class interval, use the formula: \[ \text{Midpoint} = \frac{\text{Lower Class Limit} + \text{Upper Class Limit}}{2} \] Example for the second class (0.38–0.47): \[ \text{Midpoint} = \frac{0.38 + 0.47}{2} = 0.425 \] Thus, the midpoint for the second class is 0.425 inches. Note: This table and calculations help understand the spread and central tendencies in the given data set.
### Lesson 2.1 Frequency Distributions **Instruction Step: 1 of 2** #### Frequency Distribution Table Below is a frequency table representing the distribution of the length of screws (in inches). | Class Length (in inches) | Frequency | |--------------------------|-----------| | 0.28–0.37 | 13 | | 0.38–0.47 | 12 | | 0.48–0.57 | 9 | | 0.58–0.67 | 6 | | 0.68–0.77 | 13 | **Task:** Determine the midpoint for the second class. To find the midpoint of a class interval, use the formula: \[ \text{Midpoint} = \frac{\text{Lower Class Limit} + \text{Upper Class Limit}}{2} \] Example for the second class (0.38–0.47): \[ \text{Midpoint} = \frac{0.38 + 0.47}{2} = 0.425 \] Thus, the midpoint for the second class is 0.425 inches. Note: This table and calculations help understand the spread and central tendencies in the given data set.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Lesson 2.1 Frequency Distributions
**Instruction Step: 1 of 2**
#### Frequency Distribution Table
Below is a frequency table representing the distribution of the length of screws (in inches).
| Class Length (in inches) | Frequency |
|--------------------------|-----------|
| 0.28–0.37 | 13 |
| 0.38–0.47 | 12 |
| 0.48–0.57 | 9 |
| 0.58–0.67 | 6 |
| 0.68–0.77 | 13 |
**Task:**
Determine the midpoint for the second class.
To find the midpoint of a class interval, use the formula:
\[ \text{Midpoint} = \frac{\text{Lower Class Limit} + \text{Upper Class Limit}}{2} \]
Example for the second class (0.38–0.47):
\[ \text{Midpoint} = \frac{0.38 + 0.47}{2} = 0.425 \]
Thus, the midpoint for the second class is 0.425 inches.
Note: This table and calculations help understand the spread and central tendencies in the given data set.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb9576c1-feeb-4331-aef2-2e956f1f0f27%2F33c69744-3da9-4cef-b07e-00aba762587d%2F729wwvo.jpeg&w=3840&q=75)
Transcribed Image Text:### Lesson 2.1 Frequency Distributions
**Instruction Step: 1 of 2**
#### Frequency Distribution Table
Below is a frequency table representing the distribution of the length of screws (in inches).
| Class Length (in inches) | Frequency |
|--------------------------|-----------|
| 0.28–0.37 | 13 |
| 0.38–0.47 | 12 |
| 0.48–0.57 | 9 |
| 0.58–0.67 | 6 |
| 0.68–0.77 | 13 |
**Task:**
Determine the midpoint for the second class.
To find the midpoint of a class interval, use the formula:
\[ \text{Midpoint} = \frac{\text{Lower Class Limit} + \text{Upper Class Limit}}{2} \]
Example for the second class (0.38–0.47):
\[ \text{Midpoint} = \frac{0.38 + 0.47}{2} = 0.425 \]
Thus, the midpoint for the second class is 0.425 inches.
Note: This table and calculations help understand the spread and central tendencies in the given data set.
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