ou are conducting a study to see if the proportion of voters who prefer Candidate A is significantly m chan 0.67. Thus you are performing a right-tailed test. Your sample data produce the test statistic z = 2.753. Find the p-value accurate to 4 decimal places. NOTE: Since you are given the z-score use the NORMAL DISTRIBUTION calculator with µ = 0 and o = 1 p-value = P(z > 2.753) = %3D

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### Analyzing Voter Preference Proportions: Right-Tailed Test

**Question 25:**

You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.67. Thus, you are performing a right-tailed test. Your sample data produce the test statistic \( z = 2.753 \). Find the p-value accurate to 4 decimal places.

**Instructions:**

**NOTE:** Since you are given the z-score, use the NORMAL DISTRIBUTION calculator with \( μ = 0 \) and \( σ = 1 \).

**Calculation:**

To find the p-value, determine the probability that \( z \) is greater than 2.753.

**Formula:**
\[ \text{p-value} = P(z > 2.753) = \]

**Input Field:**
*Type your calculated p-value accurate to 4 decimal places*

**Submit:**

*Click the blue "Submit Question" button to save your answer.*

**Explanation:**

In this exercise, you are testing the hypothesis that the proportion \( p \) of voters favoring Candidate A is greater than 0.67 using a right-tailed test. The given z-score is 2.753, indicating how many standard deviations the sample proportion is away from the hypothesized population proportion. Using the standard normal distribution, calculate the p-value corresponding to this z-score. If the p-value is sufficiently small, it suggests that the observed proportion significantly exceeds the hypothesized proportion of 0.67.

**Note:**

Make sure you use the standard normal distribution table or a z-score calculator to find the exact p-value for the given z-score. The result will tell you the probability of getting a test statistic as extreme as (or more extreme than) the one obtained, assuming that the null hypothesis is true.
Transcribed Image Text:### Analyzing Voter Preference Proportions: Right-Tailed Test **Question 25:** You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.67. Thus, you are performing a right-tailed test. Your sample data produce the test statistic \( z = 2.753 \). Find the p-value accurate to 4 decimal places. **Instructions:** **NOTE:** Since you are given the z-score, use the NORMAL DISTRIBUTION calculator with \( μ = 0 \) and \( σ = 1 \). **Calculation:** To find the p-value, determine the probability that \( z \) is greater than 2.753. **Formula:** \[ \text{p-value} = P(z > 2.753) = \] **Input Field:** *Type your calculated p-value accurate to 4 decimal places* **Submit:** *Click the blue "Submit Question" button to save your answer.* **Explanation:** In this exercise, you are testing the hypothesis that the proportion \( p \) of voters favoring Candidate A is greater than 0.67 using a right-tailed test. The given z-score is 2.753, indicating how many standard deviations the sample proportion is away from the hypothesized population proportion. Using the standard normal distribution, calculate the p-value corresponding to this z-score. If the p-value is sufficiently small, it suggests that the observed proportion significantly exceeds the hypothesized proportion of 0.67. **Note:** Make sure you use the standard normal distribution table or a z-score calculator to find the exact p-value for the given z-score. The result will tell you the probability of getting a test statistic as extreme as (or more extreme than) the one obtained, assuming that the null hypothesis is true.
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