Answered: STATION NORTHINGS 0+000 11475.55 PI1…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

DO ONLY PART 1

Coordinates of Intersecting Points
Length of Chord of the First Simple Curve is 132.24 m
Degree of Curve of the first curve of the compound Curve is 8 degrees
The deflection angle of Sta. 1+140 from PC3 is 15°28' and the corresponding chord distance is 94.49 m.
REQUIRED:
1. The azimuth and distance of the tangent lines.
2. The Intersecting Angle (I), radius (R), tangent distance (T), Length of Curve (Lc) of the curves
3. The Stationing of PC, PT, PC2, PCC, PT2, PC3, PRC, PT3 and End of Project
Fill up your answer on the given table.
Stationing at the beginning of the Road is equal to (0+000) + 77

STATION NORTHINGS EASTINGS
0+000
11475.55
8927.24
PI1
11478.80
9291.91
P12
11179.37
9546.66
P13
9282.44
P14
9433.48
V1
11245.48
9490.41
V2
11074.50
9472.69
END 10203.85
9016.99
LINE
0-PI1
PI1-V1
V1-V2
V2-P13
P13-P14
PI4-END
CURVE
1stCurve
2nd Curve
3rd Curve
4th Curve
5th Curve
PC
PT
PC2
PCC
PT2
PC3
PRC
PT3
END
10804.76
10512.37
AZIMUTH
I
0+000
STATIONING
DISTANCE
R
T
END OF ROAD
LC
13
15
R5
PC1
R1
LC1
11
R3
P13
PI1
PC3
PT3
PT1
R2,
12
1+140
LC4
PRC
LC5
Lc2
Lc3
PT2
PC2
R4
14
P14
V1
PCC
V2
P12

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