Problem no. 4: The common tangent BC of the reverse curve is 300m and has a bearing of 543°E. AB is a tangent of the first curve whose bearing is N75°E. CD is a tangent of the 2nd curve whose bearing is N54°E. R1=700m and the point of intersection of the first curve is at station 1 + 110. 26. Find the Central angle of the first curve 27. Find the Central angle of the second curve 28. Find the radius of the second curve 29. Find the stationing of PC 30. Find the stationing of PT

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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EDIT: The common tangent of the reverse curve is 500. ANSWER CORRECTLY AND PROVIDE DETAILED COMPUTATIONS. KINDLY DRAW THE ILLUSTRATION

Problem no. 4: The common tangent BC of the reverse curve is 300m and has a bearing of 543°E. AB is a tangent
of the first curve whose bearing is N75°E. CD is a tangent of the 2nd curve whose bearing is N54°E. R1=700m and
the point of intersection of the first curve is at station 1 + 110.
26. Find the Central angle of the first curve
27. Find the Central angle of the second curve
28. Find the radius of the second curve
29. Find the stationing of PC
30. Find the stationing of PT
Transcribed Image Text:Problem no. 4: The common tangent BC of the reverse curve is 300m and has a bearing of 543°E. AB is a tangent of the first curve whose bearing is N75°E. CD is a tangent of the 2nd curve whose bearing is N54°E. R1=700m and the point of intersection of the first curve is at station 1 + 110. 26. Find the Central angle of the first curve 27. Find the Central angle of the second curve 28. Find the radius of the second curve 29. Find the stationing of PC 30. Find the stationing of PT
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