Standardization of a Solution A 50.00 mL aliquot portion of 0.01020 M KIO3 solution was transferred into a conical flask. After adding 2.0 g KI and 2 mL of 6M HCl, the mixture was titrated with 31.32 mL of the Na2S2O3 solution to the starch end point. Calculate the number of mmoles of IO3-. mmoles 103- How many mmoles of 12 was released after the addition of KI? mmoles I: How many mmoles Na2S2O3 reacted with the Iz produced? mmoles Na2S₂O3- What is the molarity of the Na2S2O3 solution? M Na2S2O3 Write the half reaction representing the transformation of OC1- (hypochlorite ion) to Cl-(chloride) in acidic medium. Reduction Half Reaction: Write the half reaction representing the transformation of 1- (iodide ion) to I2 (iodine) in acidic medium. Reduction Half Reaction: Analysis of Household Bleaching Agent The composition of a commercially available household bleaching agent is advertised as 5% (w/v) NaOC1. Calculate the number of mmoles of NaOCI present in 50 mL of the bleaching agent. mmol . Calculate the number of mmoles of Na2S2O3 that will react with the 12 that is generated from the reactions of the KI with the NaOCI present in 50-mL of the bleaching agent. mmol Na2S₂O3 How many mL of 0.1025 M Na2S2O3 are required to deliver this amount? mL
Standardization of a Solution A 50.00 mL aliquot portion of 0.01020 M KIO3 solution was transferred into a conical flask. After adding 2.0 g KI and 2 mL of 6M HCl, the mixture was titrated with 31.32 mL of the Na2S2O3 solution to the starch end point. Calculate the number of mmoles of IO3-. mmoles 103- How many mmoles of 12 was released after the addition of KI? mmoles I: How many mmoles Na2S2O3 reacted with the Iz produced? mmoles Na2S₂O3- What is the molarity of the Na2S2O3 solution? M Na2S2O3 Write the half reaction representing the transformation of OC1- (hypochlorite ion) to Cl-(chloride) in acidic medium. Reduction Half Reaction: Write the half reaction representing the transformation of 1- (iodide ion) to I2 (iodine) in acidic medium. Reduction Half Reaction: Analysis of Household Bleaching Agent The composition of a commercially available household bleaching agent is advertised as 5% (w/v) NaOC1. Calculate the number of mmoles of NaOCI present in 50 mL of the bleaching agent. mmol . Calculate the number of mmoles of Na2S2O3 that will react with the 12 that is generated from the reactions of the KI with the NaOCI present in 50-mL of the bleaching agent. mmol Na2S₂O3 How many mL of 0.1025 M Na2S2O3 are required to deliver this amount? mL
Chapter31: Introduction To Analytical Separations
Section: Chapter Questions
Problem 31.19QAP
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Transcribed Image Text:Standardization of a Solution
A 50.00 mL aliquot portion of 0.01020 M KIO3 solution was transferred into a conical flask. After adding 2.0 g
KI and 2 mL of 6M HC1, the mixture was titrated with 31.32 mL of the Na2S2O3 solution to the starch end point.
Calculate the number of mmoles of IO3-.
mmoles 103-
How many mmoles of 12 was released after the addition of KI?
mmoles I₂
How many mmoles Na2S2O3 reacted with the 12 produced?
mmoles Na2S2O3-
What is the molarity of the Na2S2O3 solution?
M Na2S2O3
Write the half reaction representing the transformation of OC1- (hypochlorite ion) to Cl-(chloride) in acidic medium.
Reduction Half Reaction:
Write the half reaction representing the transformation of 1- (iodide ion) to 12 (iodine) in acidic medium.
Reduction Half Reaction:
Analysis of Household Bleaching Agent
The composition of a commercially available household bleaching agent is advertised as 5% (w/v) NaOC1.
. Calculate the number of mmoles of NaOCl present in 50 mL of the bleaching agent.
mmol
. Calculate the number of mmoles of Na2S2O3 that will react with the Iz that is generated from the reactions of the KI
with the NaOCI present in 50-mL of the bleaching agent.
mmol Na2S₂O3
How many mL of 0.1025 M Na2S2O3 are required to deliver this amount?
mL
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