How much drying agent, M|SO4, would be needed for drying of 20mL dichloromethane solution that contains 0.01% water, knowing that each mole of MgSO, can absorb 7 moles of H,0?
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- Oral rehydration salts are stated to contain the following components: Sodium Chloride 3.5g Potassium Chloride 1.5g Sodium Citrate 2.9g Anhydrous Glucose 20.0g 8.342 g of oral rehydration salts are dissolved in 500 ml of water. 5 ml of the solution is diluted to 100 ml and then 5 ml is taken from the diluted sample and is diluted to 100 ml. The sodium content of the sample is then determined by flame photometry. The sodium salts used to prepare the mixture were: Trisodium citrate hydrate (C6H5Na3O7, 2H2O) MW 294.1 and sodium chloride (NaCl) NW 58.5. Atomic weight of Na = 23. The content of Na in the diluted sample was determined to be 0.3210 mg/100 ml. Determine the % of stated content of Na in the sample. The stated should be 104.5, how??When a Vitamin C (ascorbic acid; MM = 176.12 g mol-1) tablet is crushed, dissolved and titrated with 0.0340 M KIO3(aq) to a purple/blue endpoint (given by a starch indicator), the volume of KIO3 used is 29.80 mL. If 60 mg of ascorbic acid is the recommended dietary allowance (i.e., 100% of the RDA), then what is the % RDA for the Vitamin C in the tablet? KIO3(aq) + 5 KI + 6 H+ → 3 I2(aq) + 3 H2O I2 (aq) + ascorbic acid → 2 I- + dehydroascorbic acidThe ethyl acetate concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 19.00-mL portion of the diluted solution was refluxed with 40.00 mL of 0.04601 M KOH: CH3 СОО С2H; + ОН — СH3 COO + C2H; ОН After cooling, the excess OH was back-titrated with 3.02 mL of 0.05056 M H2 SO4. Calculate the amount of ethyl acetate (88.11 g/mol) in the original sample in grams. Amount of ethyl acetate =
- Calculate the amount of potassium chloride needed to prepare a 60 mL ORS based on the given procedure: Dissolve 0.25g NaCi, 0.20g NaHCO3, 0.35g KCI, and 1.5g of glucose in 100 ml distilled water using a 250 mL capacity beaker. (MW: Na: 23, K: 39, CI: 35, H: 1, C: 12, O: 16) 0.9 g O 0.12 g 0.15 g O 0.21 gHexanoic acid was added to an immiscible biphasic solvent system, water and CCl4 at 20.0OC and the equilibrium concentrations of hexanoic acid were determined to be 3.66 g/L in H2O and 67.0 g/L in CCl4. Caluclate the distrubution coeffiecent (D2) of hexanoic acid in water with respect to CCl4.After 10.0 mL of an aqueous solution containing 1.235 mg of a drug extracted with 5.0 mL of toluene the aqueous layer was found to contain 0.346 mg of the compound. (a) Calculate the distribution coefficient for the drug between the two solvents. (b) How many 10.0-mL extractions would be required to recover 99.0% of the drug from 20.0 mL of water? What volume of toluene would be used?
- Stoichiometry: Prolonged exposure of some functionalities to the eluent (methanol) in this experiment may lead to undesirable reactions. In one case, Acetylsalicylic acid (Aspirin) can react with methanol to form salicylic acid and methyl acetate. If 800 mg of Acetylsalicylic acid and 1 mL of Methanol undergoes such a side reaction (known as "Methanolysis") to completion: (a) write a balanced equation (draw all molecules instead of writing chemical formulas), (b) what is the limiting reagent? (c) predict the grams of salicylic acid and methyl acetate to be produced in this process. Show calculations. Hint: you can determine the grams of 1 mL of Methanol through its density.Please answer fast(d) A sample contains a mixture of ammonium carbonate (NH4)2CO3, sodium carbonate Na2CO3, and sodium chloride NaCl. Thermogravimetric analysis indicates that a 0.0965-g portion of this sample loses 0.0574 g over a temperature range of 50-75 oC and then loses another 0.0124 g at 800 oC.(i) What causes the weight loss at 50-75 oC? (ii) What species will remain after being heated to 800 oC? (iii) What is the composition of the original sample? Given: Atomic masses: H = 1.008; C = 12.011; N = 14.007; Na = 22.99; O = 15.999;Cl = 35.45.
- In what proportion may the Manufacturing pharmacist mix 20%, 15%, 5% and 3% ZnO to produce 10% ZnO ointment?Exactly 5.00-mL aliquots of a methanol solution containing an unknown amount of methamphetamine were measured into 50.00-mL volumetric flasks. The following volumes of a standard methanol solution of methamphetamine containing 2.000 ug/mL of methamphetamine were then introduced into each flask and the mixture was diluted to volume with 0.000, 0.500, 1.00, 1.50 and 2.00 mL of methanol. 1 uL of these solutions was then injected into a gas chromatograph and the following respective peak areas were measured: 326, 480, 641, 802, and 956 (all peak areas were x 103). Plot the data Using the plot from (a), calculate the concentration of methamphetamine in the unknown. Derive a least squares equation from the data. Calculate the concentration of methamphetamine from the equation in (c).How to prepare, 0.8 N of MgS04 (Mol. wt. 104 and the charge is 2) in 0.5 L. Dissolve 20.8 grams of MgSO4 in 500 ml of H2O. Dissolve 41.6 grams of MgS04 in 0.5L of H2O. Dissolve 27 grams of MgSO4 in 0.5L of H2o. Dissolve 18 grams of MgSO4 in 0.5L of H2O. A Moving to the next question prevents changes to this answer.