5 g of cobalt carbonate and 13 mL of concentrated hydrochloric acid were used. In another glass, prepare a solution with 8.4 mL of anhydrous ethylenediamine and 2.8 mL of concentrated hydrochloric acid. They are mixed and added and 6.5 mL of peroxide were added to it. 30% hydrogen, then concentrated hydrochloric acid is added, followed by 60 mL of ethanol. 5.1234 g were obtained orange solid [Co (en) 3] Cl3 What is the percentage yield of the reaction. The reactions are shown in the images.

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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5 g of cobalt carbonate and 13 mL of concentrated hydrochloric acid were used.

In another glass, prepare a solution with 8.4 mL of anhydrous ethylenediamine and 2.8 mL of concentrated hydrochloric acid.

They are mixed and added and 6.5 mL of peroxide were added to it.
30% hydrogen, then
concentrated hydrochloric acid is added, followed by
60 mL of ethanol.

5.1234 g were obtained orange solid [Co (en) 3] Cl3

What is the percentage yield of the reaction.

The reactions are shown in the images.

COCO3 +2HCI +5H2 O
Solubleney
Insoluble
an 120
2
HEN
2HN
He N ~wHz o 2HC)
Cen)
→ [Co Ceul3 ]Cla + 6Hz O +6HC)
Transcribed Image Text:COCO3 +2HCI +5H2 O Solubleney Insoluble an 120 2 HEN 2HN He N ~wHz o 2HC) Cen) → [Co Ceul3 ]Cla + 6Hz O +6HC)
の
エ
平W
+ HzOz
[Co Len),] Cl3
Transcribed Image Text:の エ 平W + HzOz [Co Len),] Cl3
Expert Solution
Step 1-Introduction

The balanced chemical equation has the number of atoms of the reactants equal to the number of atoms belongs to the products. So the number of moles of the reactants and products becomes equal. The relation between the mass and molar mass of a component can be used to determine the moles.

Number of moles=Mass of the componentMolar mass   ...(1)

The theoretical yield associated with a reaction is obtained from the stoichiometric equation and assuming the maximum conventions to the products. But the obtained yield of a chemical is an experimental quantity. The ratio of the obtained yield to the theoretical yield furnishes the percentage yield of the reaction.

Percentage yield=Actual yield of the reactionTheoretical yield×100   ...(2)

 

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