standard deviation calculated fromviewed values for a continuous, numerical variable: A) Quantifies the uncertainty associated with the estimate of the mean B) used to calculate the standard error C) Represents the standard deviation of the sampling distribution
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Q: The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a…
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Q: The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a…
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- Distribution of exam scores follows the normal distribution, with a mean of 70 percent and a standard deviation of 10. a) What percent of students scored 85 percent or higher on the exam? b) What was the lowest grade of the students scoring the top five percent of the scores? c) What was the percentage of students earning between 75 and 85 percent on the exam?a) State the mean and standard deviation of the standard normal curve. b) Find the z-score for which 95% of the distribution’s area lies between –z and z. c) Extending the meaning in part b, only 2.5% of z-scores would lie above ________.Biologists studying the healing of skin wounds measured the rate at which new cells closed a razor cut made in the skin of anesthetized newt. Here are the sorted data from 12 news measured in 2. micrometers per hour (microm/hr): 11 12 18 22 22 23 23 26 29 29 30 31 (a) Using the data compute the sample mean of the healing rates. Include appropriate notation and units. Sample mean: (b) Estimate the sample standard deviation (SD). Include appropriate notation and units. Sample SD: (c) Compute and interpret z-score for the healing rate of 26 microm/hr. z-score = Interpretation:
- carbon monoxide in the air in U.S. cities is less than 2.32 parts per million. It was found that the mean amount Test a claim that the mean amount e standard deviation is 2.12 parts per million. At a = 0.05, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed. carbon monoxide in the air for the random sample of 64 cities is 2.41 parts per million and the (a) Identify the claim and state Ho and H. Which of the following correctly states Ho and H? AA :°H "H (Type integers or decimals. Do not round.) The claim is the V hypothesis. (b) Use technology to find the critical value(s) and identify the rejection region(s). The critical value(s) is/are to =U- (Use a comma to separate answers as needed. Round to two decimal places as needed.) Choose the graph which shows the rejection region. O B. "a O of (c) Find the standardized test statistic, t. The standardized test statistic is t=- (Round to two decimal nlaces as neadedThe overhead reach distances of adult females are normally distributed with a mean of 205.5 cm and a standard deviation of 7.8 cm. a. Find the probability that an individual distance is greater than 218.90 cm. b. Find the probability that the mean for 15 randomly selected distances is greater than 203.30 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?The overhead reach distances of adult females are normally distributed with a mean of 202.5 cm and a standard deviation of 8.3 cm. a. Find the probability that an individual distance is greater than 212.50 cm. b. Find the probability that the mean for 20 randomly selected distances is greater than 200.70 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?
- The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm and a standard deviation of 8.3 cm. a. Find the probability that an individual distance is greater than 210.90 cm. b. Find the probability that the mean for 15 randomly selected distances is greater than 195.70 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm. A) Find a probability that an individual distance is greater than 214.30 cm. B) Find the probability that the mean for 20 randomly selected distances is greater than 203.20 cm C) Why can the normal distribution be used in part (b), eventhough the sample size does not exceed 30 a. The probability is_______ (Round to four decimal places as needed) b. The probability is_______ (Round to four decimal places as needed) c. Choose the correct answer A. The normal distribution can be used because the original population has a normal distribution B. The normal distribution can be used because the mean is large C. The normal distribution can be used becuase the probability is less than 0.5 D. The normal distribution can be used because the finite population correction factor is smallUse the Central Limit Theorem to find the mean and standard error of the mean of the sampling distribution. Then sketch a graph of the sampling distribution. The mean price of photo printers on a website is $227 with a standard deviation of $68. Random samples of size 21 are drawn from this population and the mean of each sample is determined.
- d) For a standard normal distribution, find the probability a score is lower than 2.37 standard deviations above the mean? e) For a standard normal distribution, find the probability a score is between the mean and 2.37 standard deviations above the mean?Find the standard deviation, s, of sample data summarized in the frequency distribution table given below by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 9.0 n(n - 1) 37-43 44-50 51-57 58-64 65-71 Interval 30-36 Frequency 1 20 43 19 6. Standard deviation (Round to one decimal place as needed.) Question Viewer Enter your answer in the answer box and then click Check Answer. Check Answer Clear All 1 part remaining Conyright 9 2020 Pearson Education Inc. All rights reserved. I Terms of Use | Privacy Policy I Permissions Contact UsAmong coffee drinkers men drink a mean of 3.2 cups per day with a standard deviation of 0.8 cup. Assume the number of cups per day follows a normal distribution a) what proportion drink 2 cup per day or more? b) what proportion drink no more than 4 cups per day? c) if the top 5% of coffee drinkers are considered heavy coffee drinkers what is the minimum number of cups consumed by a heavy coffee drinker? Hint: find 95 percentile
