Among coffee drinkers men drink a mean of 3.2 cups per day with a standard deviation of 0.8 cups. Assume the number of coffee drinks per day follows a normal distribution  A) what proportion drink 2 cup per day or more? B) what proportion drink no more than 4cup per day? C) If the top 5% of coffee drinkers are considered heavy coffee drinkers what is the minimum number of cups per day consumed by a heavy coffee drinker? Hint: find the 95th percentile

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Among coffee drinkers men drink a mean of 3.2 cups per day with a standard deviation of 0.8 cups. Assume the number of coffee drinks per day follows a normal distribution 

A) what proportion drink 2 cup per day or more?

B) what proportion drink no more than 4cup per day?

C) If the top 5% of coffee drinkers are considered heavy coffee drinkers what is the minimum number of cups per day consumed by a heavy coffee drinker? Hint: find the 95th percentile

Expert Solution
Step 1

Given Information : Among coffee drinkers men drink a mean of 3.2 cups per day with a standard deviation of 0.8 cups. Assume the number of coffee drinks per day follows a normal distribution . 

Define random variable X denotes number of coffee drinks per day.  

Here, X ~> Normal (μ=3.2, σ=0.8

(a)

We need to compute . The corresponding z-value needed to be computed is : 

Probability homework question answer, step 1, image 1

Therefore, we get that 

Probability homework question answer, step 1, image 2

Proportion drink 2 cup per day or more = 93.32% 

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