University of Florida football programs are printed 1 week prior to each home game. Attendance averages 75,000 screaming and loyal Gators fans, of whom two-thirds usually buy the program, following a normal distribution, for $5 each. Unsoldprograms are sent to a recycling center that pays only 10 cents per program. The standard deviation is 10,000 programs, and the cost to print each program is $1. Refer to the standard normal table for z-values.a) What is the cost of underestimating demand for each program?Cs = $ (round your response to two decimal places).

From the above given data the following solution is provided below

Answered: University of Florida football programs…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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a group of diners were asked how much they would pay for a meal. their responses were $7.50,$8.25,$9.00,$8.00,$7.25,$7.50,$8.00,$7.00. find the mean find the median write the 5-number summary for this data find the standard deviation of this data
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In the 1992 presidential election, Alaska's 40 election districts averaged 1833 votes per district for President Clinton. The standard deviation was 558. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(Correct,Correct) b. Is 1833 a population mean or a sample mean? Select an answer Sample Mean Population Mean c. Find the probability that a randomly selected district had fewer than 1915 votes for President Clinton. d. Find the probability that a randomly selected district had between 1813 and 1922 votes for President Clinton. e. Find the third quartile for votes for President Clinton. Round your answer to the nearest whole number.
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